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boyakko [2]
3 years ago
14

A cylinder’s radius is reduced to two-fifths its original size and the height is quadrupled. How has the volume of the cylinder

changed?
Mathematics
1 answer:
Damm [24]3 years ago
8 0
Let the original volume be pi *r^2* h where  r = radius and h = height.

The new volume will be pi *(2/5 r)^2 * 4h  =  pi*4/25 r^2 4h

pi*4/25r^2 * 4h  /  pi r^2 h  = 4/25 * 4 = 16/25

The volume has been reduced  by  factor of 16/25.
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Answer:

0.00075

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Step-by-step explanation:

Let E1 be the event that A dies within next 20 years and E2 be the event that B dies within next 20 years.

Probability that E1 occurs = P(E1) = 0.025

Probability that E2 occurs= P(E2)= 0.030

Since the two events does not depend on each other, E1 and E2 are independent events.

For two independents E1 and E2 , the probability that both E1 and E2 occurs simultaneously is P(E1 ∩ E2) is given by:

P(E1 ∩ E2) = P(E1)*P(E2)

Probability that both A and B dies in next 20 years = 0.025\times0.03=0.00075

Probability that A will die and B will not die is given by=

P(E1 ∩ E2') = P(E1) - P(E1 ∩ E2) = 0.025 - 0.00075 = 0.02425.

Probability that neither A nor B dies is given by=

P(E1' ∩ E2') = 1 - [ P(E1 ∪ E2) ] = 1 - [ P(E1) + P(E2) - P(E1 ∩ E2) ]

                                                = 1 - [0.025 + 0.030 - 0.00075] = 0.94575

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