A cylinder’s radius is reduced to two-fifths its original size and the height is quadrupled. How has the volume of the cylinder
changed?
1 answer:
Let the original volume be pi *r^2* h where r = radius and h = height.
The new volume will be pi *(2/5 r)^2 * 4h = pi*4/25 r^2 4h
pi*4/25r^2 * 4h / pi r^2 h = 4/25 * 4 = 16/25
The volume has been reduced by factor of 16/25.
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