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boyakko [2]
3 years ago
14

A cylinder’s radius is reduced to two-fifths its original size and the height is quadrupled. How has the volume of the cylinder

changed?
Mathematics
1 answer:
Damm [24]3 years ago
8 0
Let the original volume be pi *r^2* h where  r = radius and h = height.

The new volume will be pi *(2/5 r)^2 * 4h  =  pi*4/25 r^2 4h

pi*4/25r^2 * 4h  /  pi r^2 h  = 4/25 * 4 = 16/25

The volume has been reduced  by  factor of 16/25.
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