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boyakko [2]
3 years ago
14

A cylinder’s radius is reduced to two-fifths its original size and the height is quadrupled. How has the volume of the cylinder

changed?
Mathematics
1 answer:
Damm [24]3 years ago
8 0
Let the original volume be pi *r^2* h where  r = radius and h = height.

The new volume will be pi *(2/5 r)^2 * 4h  =  pi*4/25 r^2 4h

pi*4/25r^2 * 4h  /  pi r^2 h  = 4/25 * 4 = 16/25

The volume has been reduced  by  factor of 16/25.
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laila [671]

Answer:

<u>The correct answer is B. ∠X = 28.6°, ∠Y = 31.2°, ∠Z = 120.2°</u>

Step-by-step explanation:

Let's recall that for solving a SSS triangle, we :

1. Use the Law of Cosines first to calculate one of the angles

2. Use The Law of Cosines again to find another angle

3. Finally use angles of a triangle add to 180° to find the last angle.

1. Cos x = (9² + 15² - 8.3²/2 * 9 * 15)

Cos x = (81 + 225 - 68.89/270)

Cos x = 0.878

x = Cos ⁻¹ (0.878)

x = 28.6° (rounding to the next tenth)

2. Cos y = (8.3² + 15² - 9²/2 * 8.3 * 15)

Cos y = (68.89 + 225 - 81/249)

Cos y = 0.855

x = Cos ⁻¹ (0.855)

x = 31.2° (rounding to the next tenth)

3. z = 180 - 31.2 - 28.6

z = 120.2°

<u>The correct answer is B. ∠X = 28.6°, ∠Y = 31.2°, ∠Z = 120.2°</u>

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3 years ago
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Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
determinati cel mai mic multiplu comun al urmatoarelor numere naturale a-36,48,54;b-30,45,75;c-48,60,72;d-90,24,72;e-75,100,150;
fenix001 [56]
<span>f-72,108,144 is the answer i hop it helps you</span>
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