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aleksklad [387]
3 years ago
13

Use the words factor, product, quotient, and sum to describe the parts of.

Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
7 0

Answer:

A factor is a number to multiply.

A product is the answer to a multiplction problem.

Aquotient is the answer to a divison problem.

A sum is the answer to a addition problem.

Step-by-step explanation:

I do not know if thats what you extaly wanted but thats what they all mean. I do not know because your question is inexplicable and doesnt reall have a question to it.

PIT_PIT [208]3 years ago
6 0

Answer:

That's all I know

Step-by-step explanation:

Hope it Helps

You might be interested in
Write a quadratic function whose zeros are -3 and -4
andreev551 [17]

Answer:

  f(x) = (x -(-3))(x -(-4))

Step-by-step explanation:

The function can be written as the product of binomial terms whose values are zero at the given zeros.

  (x -(-3)) is one such term

  (x -(-4)) is another such term

The product of these is the desired quadratic function. In the form easiest to write, it is ...

  f(x) = (x -(-3))(x -(-4))

This can be "simplified" to ...

  f(x) = (x +3)(x +4) . . . . simplifying the signs

  f(x) = x^2 +7x +12 . . . . multiplying it out

6 0
4 years ago
What is the answer????
Monica [59]

Answer:

Step-by-step explanation:

To find the breadth use Pythagorean theorem

Breadth² = diagonal² - length²

               = 34² - 30²

               = 1156 - 900

               = 256

Breadth = √256 = 16 cm

Breadth = 16 cm

Perimeter = 2*(length + breadth) = 2*(30 + 16) = 2*46 = 92 cm

Area = length * breadth = 30 *16 = 480 cm²

3 0
2 years ago
Read 2 more answers
Which of the following is polynomial?
lawyer [7]

Answer:

x^2-1 has two terms without any negative exponent. so it is a polynomial.

Step-by-step explanation:

A polynomial is a expression with more than one terms.

The expression with negative exponent is not a polynomial.

Expression in the denominator is also not a polynomial

x^2-1 has two terms without any negative exponent. so it is a polynomial.

option B,C and D has negative exponents, so it is not a polynomial.

7 0
3 years ago
Use a calculator to find the value of each expression. Round your answer to the nearest hundredth.
inysia [295]

Answer:

Arcsin(1/5) = 0.20

Arcsin(-0.34) = -0.35

Arcsin(0.6) = 0.64

Step-by-step explanation:

Using a calculator we can find the value of each expression:

Arcsin(1/5) = 0.20135792079, rounding to the nearest hundredth we have that: Arcsin(1/5) = 0.20.

Arcsin(-0.34) = -0.346916897527, rounding to the nearest hundredth we have that: Arcsin(-0.34) = -0.35

Arcsin(0.6) = 0.643501108793, rounding to the nearest hundredth we have that: Arcsin(0.6) = 0.64

8 0
3 years ago
ANSWER ALL 5 PARTS.
N76 [4]
A function f from a set A to a set B is defined as a relation that assings to each element  x in the set A exactly one element y in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing bell peppers. If each side of the tomato patch is x feet, then we have a square patch as shown in the Figure below.

1.a) Write the function Wa(x) representing the width of the bell pepper patch.

We know that she wants its width to be half the width of the tomato patch. Let x be the width of the tomato patch, then the function that matches this statement is:

\boxed{Wa(x)=\frac{x}{2}}

1.b) Write the function La(x) representing the length of the bell pepper patch.

In this case Melissa wants <span>its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:

</span>\boxed{La(x)=x+2}
<span>
2. Ar</span>ea of the bell pepper patch in terms of x.

Given that the bell pepper patch is a rectangle, then t<span>he area of a rectangle is the product of the length and width. So:

</span>A=(\frac{x}{2})(x+2) \\ \\ \therefore \boxed{A=\frac{x(x+2)}{2}}
<span>
3. C</span><span>ombined area of the tomato patch and the bell pepper patch.

This function is the sum of both the area of the tomato patch and the bell pepper patch. So:

</span>Aar(x)=x^{2}+\frac{x(x+2)}{2} \rightarrow Aar(x)=x^{2}+ \frac{x^{2}}{2}+x \rightarrow Aar(x)=\frac{3x^{2}}{2}+x \\ \\ \therefore \boxed{Aar(x)=\frac{x(3x+2)}{2}}
<span>
4. W</span>rite the function Aa(x) for the remaining planting area in the garden.

The remaining planting area in the garden are the rectangles in red. So we need to subtract the width of the bell pepper patch from the width of the tomato patch and multiply it by 2. In mathematical language this is given by:<span>

</span>Aa(x)=2(x-\frac{x}{2}) \rightarrow Aa(x)=x

5. 
Find the area of the remaining space in the garden after planting tomatoes and bell peppers.

Given that <span>Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:

</span>31.5=\frac{x(x+2)}{2} \rightarrow x^{2}+2x-64=0 \\ \\ solving \ for \ x: \\ x=7.06
<span>
Therefore the area of the remaining space is:

</span>\boxed{Aa(7.06)=7.06ft^{2}}

6 0
4 years ago
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