All categories

3 years ago

Draw a figure with the given perimeter. 6 units

1 answer:

6 0

<span>We have to draw a figure with a perimeter 6 units. If we want to draw a rectangle it can`t be a 3 by 2 because it has a perimeter 2*2 + 2*3 = 4 + 6 = 10 units. It must be a 2 by 1 rectangle ( 2*2 + 2*1 = 4 + 2 = 6 units ).</span>

You might be interested in

A square field has an area of 10 square miles. What is the approximate length, to the nearest thousandth, of one side of this fi

Mice21 [21]

Answer: A

Step-by-step explanation: square has 4 sides 10/4=2.5

4 0

3 years ago

The two non-parallel sides of an isosceles trapezoid are each 7 feet long. The longer of the two bases measures 22 feet long. Th

Orlov [11]

The length of the diagonal and the shorter base are 17. 24 feet and 18. 7 feet long respectively.

<h3>How to determine the length</h3>

The cosine rule is given as;

$c = \sqrt{a^2 + b^2 - 2ab cos \alpha }$

c = length of the diagonal

a = base length = 22 feet

b = 7 feet

$c = \sqrt{7^2 + 22^2 - 2 * 7 * 22 cos 40}$

$c = \sqrt{533 - 308 * 0. 7660}$

$c = \sqrt{533 - 235. 93}$

$c = \sqrt{297. 072}$

$c = 17. 24$ feet

Using sine rule

$\frac{a}{sin A } = \frac{c}{sin C}$

$\frac{a}{sin 70} = \frac{17. 24}{sin 40}$

Cross multiply

$a$ × $sin 60$ = $c$ × $sin 70$

$a$ × $0. 8660$ = $17. 24$ × $0. 9397$

$a = \frac{16. 20}{0. 8660}$

a = 18. 7 feet long

Thus, the length of the diagonal and the shorter base are 17. 24 feet and 18. 7 feet long respectively.

Learn more about isosceles trapezoid here:

brainly.com/question/10187910

#SPJ1

5 0

2 years ago

There are two students Mark and John.

V125BC [204]

Answer:

Step-by-step explanation:

6 0

3 years ago

The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6

viktelen [127]

Answer:

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

The proportion of contracts involved between five and 10 inclusive bidders is 0.5.

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders No. contracts Relative frequency of contracts

2 6 6/102=0.0588

3 20 20/102=0.1961

4 24 24/102=0.2353

5 18 18/102=0.1765

6 13 13/102=0.1275

7 7 7/102=0.0686

8 5 5/102=0.049

9 6 6/102=0.0588

10 2 2/102=0.0196

11 1 1/102=0.0098

Total 102

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

We have to find proportion of contracts involved between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The proportion of contracts involved between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10= Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

8 0

3 years ago

Which points are on the graph of g(x) = (1/5)^x

11111nata11111 [884]

Answer:

A) The point( -1 , 5) is satisfies the given graph $g(x) = (\frac{1}{5} )^{x}$

B) The point( 3 , 1/125) is satisfies the given graph $g(x) = (\frac{1}{5} )^{x}$

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given graph

y = $g(x) = (\frac{1}{5} )^{x}$

Put the point ( -1 , 5)

Put y =5 and x =-1

$5 = (\frac{1}{5} )^{-1} = 5$

The point( -1 , 5) is satisfies the given graph

ii)

Given graph

y = $g(x) = (\frac{1}{5} )^{x}$

$\frac{1}{125} = (\frac{1}{5} )^{3} = \frac{1}{125}$

The point( 3 , 1/125) is satisfies the given graph $g(x) = (\frac{1}{5} )^{x}$

7 0

3 years ago