Draw a figure with the given perimeter. 6 units

1 answer:

6 0

<span>We have to draw a figure with a perimeter 6 units. If we want to draw a rectangle it can`t be a 3 by 2 because it has a perimeter 2*2 + 2*3 = 4 + 6 = 10 units. It must be a 2 by 1 rectangle ( 2*2 + 2*1 = 4 + 2 = 6 units ).</span>

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Express 10500 in term if it's prime factor

Shkiper50 [21]

2 | 10500
2 ! 5250
3 | 2625
5 | 875
5 | 175
5 | 35
7
The prime factors are 2*2*3*5*5*5*7 or 2^2*3*5^3*7

3 0

3 years ago

Barbara buys

docker41 [41]

Answer

yes it is correct

Step-by-step explanation:

6 0

3 years ago

Sam needs to make a long-distance call from a pay phone. With his prepaid phone card, he will be charged $1.00 to connect and $0

Mademuasel [1]

Answer: The required system of equations representing the given situation is

$y=1+0.5x\\\\y=3+0.25x$

Step-by-step explanation: Given that Sam needs to make a long-distance call from a pay phone.

We are to write a system to represent the situation.

Let x represent the number of minutes Sam talked on the phone and y represents the total amount that he paid for the call.

According to the given information,

with prepaid phone card, Sam will be charged $1.00 to connect and $0.50 per minute.

So, the equation representing this situation is

$y=1+0.5x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Also, if Sam places a collect call with the operator he will be charged $3.00 to connect and $0.25 per minute.

So, the equation representing this situation is

$y=3+0.25x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

Thus, the required system of equations representing the given situation is

$y=1+0.5x\\\\y=3+0.25x$

3 0

3 years ago

A person 6ft tall stands 10ft from point P directly beneath a lantern hanging 30 ft above the ground. The lantern start to fall,

xxMikexx [17]

Answer:

$\frac{dL}{dt}=30 \frac{ft}{s}$

Step-by-step explanation:

In order to solve this it is always a good idea to start by drawing a diagram of the situation (See attached picture).

From the diagram we can see that we are dealing with similar triangles. We can use similar triangles to build an equation that relates the length of the shadow with the height of the lamp, so we get:

$\frac{L}{6}=\frac{10+L}{h}$

the height of the lamp can be found by subtracting the $16t^{2}$ distance the lamp falls in a given time t from the original 30ft the lamp was located at.