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Scilla [17]
3 years ago
7

Cubes of side 3cm are stacked to form a cube of side 18 cm. Find the number of cubes used.

Mathematics
1 answer:
Shalnov [3]3 years ago
6 0
18/3=6 you do this because you assume all the cubes are the same. Also because they form a cube they are proportionate to each other.
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I give yall crown please help me i need sm help PLEASEEEEEEEEEEEEEEEEEEEEEEEEE dont bs
Rudik [331]

Answer:

b

Step-by-step explanation:

3 0
2 years ago
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What is the value of x for the equation x+2/4 + 1/3 = 2x-1/6
Gnoma [55]

Answer:

1

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

x+24+13=2x−16

x+ 1 2 + 1 3 =2x+ −1 6

(x)+( 1 2 + 1 3 )=2x+ −1 6 (Combine Like Terms)

x+ 5 6 =2x+ −1 6

x+ 5 6 =2x+ −1 6

Step 2: Subtract 2x from both sides.

x+ 5 6 −2x=2x+ −1 6 −2x

−x+ 5 6 = −1 6

Step 3: Subtract 5/6 from both sides.

−x+ 5 6 − 5 6 = −1 6 − 5 6

−x=−1

Step 4: Divide both sides by -1.

−x −1 = −1 −1

x=1

7 0
3 years ago
Read 2 more answers
The diameter of a circle is 14 inches. Find the circumstance and area use 22/7
s344n2d4d5 [400]

Answer:

Circumference= 44 in

Area= 154 in²

Step-by-step explanation:

\boxed{circumference \: of \: circle = 2\pi  r}

Radius

= diameter ÷2

= 14 ÷2

= 7 in

Circumference of circle

= 2( \frac{22}{7} )(7)

= 44 in

\boxed{area \: of \: circle = \pi {r}^{2} }

Area of circle

=  \frac{22}{7} ( {7}^{2} )

= 154 in²

3 0
3 years ago
The average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed. What is
Anna35 [415]

Answer:

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

Step-by-step explanation:

We are given that the average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed.

Firstly, Let X = women's gestation period

The z score probability distribution for is given by;

         Z = \frac{ X - \mu}{\sigma} ~ N(0,1)

where, \mu = average gestation period = 270 days

            \sigma = standard deviation = 9 days

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is given by = P(261 < X < 279) = P(X < 279) - P(X \leq 261)

         P(X < 279) = P( \frac{ X - \mu}{\sigma} < \frac{279-270}{9} ) = P(Z < 1) = 0.84134

         P(X \leq 261) = P( \frac{ X - \mu}{\sigma} \leq \frac{261-270}{9} ) = P(Z \leq -1) = 1 - P(Z < 1)

                                                           = 1 - 0.84134 = 0.15866

<em>Therefore, P(261 < X < 279) = 0.84134 - 0.15866 = 0.68</em>

Hence, probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

3 0
3 years ago
Evaluate this expression if a = 2, b = -1 and c = 1.
labwork [276]
Substitute the values into the equation

2(2)+4(-1)-5(1)
4-4-5
-5
8 0
3 years ago
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