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Scilla [17]
3 years ago
7

Cubes of side 3cm are stacked to form a cube of side 18 cm. Find the number of cubes used.

Mathematics
1 answer:
Shalnov [3]3 years ago
6 0
18/3=6 you do this because you assume all the cubes are the same. Also because they form a cube they are proportionate to each other.
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Líst the key features of the quadratic function graphed.
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I think The answer is C
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Tony bought 20 raffle tickets at a fire station. The fire station sold a total of 80 raffle tickets. What is the probability tha
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If Tony bought 20 out of 80 tickets, then it would be 25% because 20 is 1/4 of 80.
Hope I helped!
8 0
2 years ago
What is the value of x? -2x + 8 = - 16
umka2103 [35]
Solve the equation
So first we subtract 8 from both sides because we apply the inverse operation.
-2x+8=-16
     -8      -8
Now we apply it and re write the equation
-2x=-24
Now the inverse operation for multiplication is division, so we apply it.
-2x=-24
------------
 -2      -2
We are left with x=8
So our final answer is x=8

Check our work
-2(8)+8=-16

CORRECT ANSWER. :)
5 0
2 years ago
Read 2 more answers
How do I do this ? I don't know how to find the midpoint in this problem
finlep [7]
If point A is the midpoint then that means line segments XA and AY are equivalent so you can set:
3x=5x-6
(now you solve for x)
2x=6
(divide by 2 on both sides)
x=3

So BASICALLY,
XA= 3x= 3(3) = 9
AY= 5x-6= 5(3)-6 =9
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5 0
2 years ago
At the bottom is a completed addition problem, with all the digits replaced by letters. Every letter represents a single digit a
Rashid [163]

Answer:

T = 5 (H = 7, M = 1); T = 7 (H = 4, M = 2); T = 9 (H = 1, M = 3)

Step-by-step explanation:

We know MH+MH+MH=TM

MH is a two digit number, and TM is also a two digit number.

MH+MH+MH=3*(MH)<100

3M<=9, meaning that M could be 1, 2, or 3.

If M=1, MH+MH+MH=3(10+H)=30+3H=TM=10*T+1

30+3H=10T+1, so 3H must include 1 in one's digit.

The only possibility is that 3H = 21, then H = 7

MH+MH+MH=17+17+17=TM=51, T = 5

If M=2, MH+MH+MH=3(20+H)=60+3H=TM=10T+2

60+3H=10T+2, so 3H must include 2 in one's digit.

The only possibility is 3H = 12, then H = 4

MH+MH+MH=24+24+24=72, T = 7

If M=3, MH+MH+MH=3(30+H)=90+3H=TM=10T+3

90+3H=10T+3, so 3H must include 3 in one's digit.

The only possibility is 3H = 3, then H =1

MH+MH+MH=31+31+31=93, T=9

4 0
2 years ago
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