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Svetach [21]
3 years ago
8

What will be 50% of 42

Mathematics
2 answers:
zimovet [89]3 years ago
7 0
Twenty one is the answer
Airida [17]3 years ago
7 0

To find 50% of 42, first write 50% as a decimal by moving the decimal point 2 places to the left to get .50.

Next, the word "of" means multiply, so we have to multiply.

(.50) × (40) = 21

Therefore, 50% of 42 is 21.

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Mr. Gordon weighs 205 pounds . Multiply his earth weight by 0.91 to find out how much he would weigh on the planet Venus. What i
Savatey [412]
When you multiply 205 by 0.91 you get 186.55 and 205 minus 186.55 is 18.45
5 0
3 years ago
Antonio invests 3000 at .10 interest compounded semianually for 12 years. Use the compound interest formula to calculate the com
marissa [1.9K]

Answer:

A=9675.299

Step-by-step explanation:

A=p(1+r)^t

A compound amount

P is the principle amount invested

r : rate ( semiannually is 0.5 )

t=years ( semiannually 12*2=24)

A=3000(1+0.10/2)^24

A=9675.299

8 0
3 years ago
Calculate the amount and compound interest on
mart [117]

Answer:

Below in bold.

Step-by-step explanation:

i) Amount = 15000(1 + 0.10)^2 = 18,150.

Interest = 3,150.

ii) Amount = 15620(1 + 0.08/2)^(3/2*2)

= 15620(1 + 0.04)^3

= 17,570.38.

Interest =1,950.38.

iii) Amount = 100000(1 + 0.04/4)^(3)

= 100000(1 + 0.01)^3

= 103,030.1

Interest = 3030.1.

7 0
3 years ago
A political candidate has asked you to conduct a poll to determine what percentage of people support him. If the candidate only
Nadusha1986 [10]

Answer:

The sample size required is, <em>n</em> = 502.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p\cdot (1-\hat p)}{n}}

The margin of error is:

MOE=z_{\alpha/2}\sqrt{\frac{\hat p\ \cdot (1-\hat p)}{n}}

Assume that 50% of the people would support this political candidate.

The margin of error is, MOE = 0.05.

The critical value of <em>z</em> for 97.5% confidence level is:

<em>z</em> = 2.24

Compute the sample size as follows:

MOE=z_{\alpha/2}\sqrt{\frac{\hat p\ \cdot (1-\hat p)}{n}}

       n=[\frac{z_{\alpha/2}\times \sqrt{\hat p(1-\hat p)}}{MOE}]^{2}

           =[\frac{2.24\times \sqrt{0.50(1-0.50)}}{0.05}]^{2}\\\\=501.76\\\\\approx 502

Thus, the sample size required is, <em>n</em> = 502.

4 0
3 years ago
How do you share 4/3 of a rope with two people
laila [671]
Well, you can't have 4/3 of a rope because 3/3 would be one whole. That is an improper fraction. It would be 1 and 1/3. If you divide that in to two, then you get 2/3. Is that the answer you were looking for?
4 0
3 years ago
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