What was his average speed rate on his way to Seattle?
Ans: 62mph
On which part of his trip did he average a faster speed rate?
Ans: When he returned home.
Answer:
$750
Step-by-step explanation:
Tim's share price changes by $2.24 -2.49 = -0.25, so the change in the value of his investment is ...
(3000 shares)(-0.25/share) = -$750
Tim takes a loss of $750 when he sells.
Answer:
The x-coordinate of the point changing at ¼cm/s
Step-by-step explanation:
Given
y = √(3 + x³)
Point (1,2)
Increment Rate = dy/dt = 3cm/s
To calculate how fast is the x-coordinate of the point changing at that instant?
First, we calculate dy/dx
if y = √(3 + x³)
dy/dx = 3x²/(2√(3 + x³))
At (x,y) = (1,2)
dy/dx = 3(1)²/(2√(3 + 1³))
dy/dx = 3/2√4
dy/dx = 3/(2*2)
dy/dx = ¾
Then we calculate dx/dt
dx/dt = dy/dt ÷ dy/dx
Where dy/dx = ¾ and dy/dt = 3
dx/dt = ¾ ÷ 3
dx/dt = ¾ * ⅓
dx/dt = ¼cm/s
The x-coordinate of the point changing at ¼cm/s
<span>3^2 + 4^2 = 5^2
answer is </span>A) 3^2 + 4^2 = 5^2
(x-3)^2 + (x+5)^2=9^2
(x^2-6x+9) + (x^2+10x+25)=81
2x^2+4x+34=81
2x^2+4x-47=0
From here just use quadratic formula
