Check the picture below.
so the surface area of the pyramid will be the sum of the areas of the base and the four triangular faces.
![\stackrel{\textit{\Large Areas}}{\stackrel{\textit{4 triangular faces}}{4\left[ \cfrac{1}{2}(7.5)(16) \right]}~~ + ~~\stackrel{\textit{rectangular base}}{(7.5)(7.5)}}\implies 240~~ + ~~56.25\implies 296.25~ft^2](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7B%5CLarge%20Areas%7D%7D%7B%5Cstackrel%7B%5Ctextit%7B4%20triangular%20faces%7D%7D%7B4%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%287.5%29%2816%29%20%5Cright%5D%7D~~%20%2B%20~~%5Cstackrel%7B%5Ctextit%7Brectangular%20base%7D%7D%7B%287.5%29%287.5%29%7D%7D%5Cimplies%20240~~%20%2B%20~~56.25%5Cimplies%20296.25~ft%5E2)
Y(2y-3)(5y-1) check using foil
I'm pretty sure that the answer is 13/40
Answer:
213 1/3
Step-by-step explanation:
Because I know where you got this question from.
Answer:
intersect at (10,-6)
Step-by-step explanation: