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VARVARA [1.3K]
3 years ago
7

Write an equation in slope intercept form of the line that passes through the given point and is parallel to the given equation.

Mathematics
1 answer:
harina [27]3 years ago
8 0
Slope=-3
y-(-6)=-3(x-(-6))
y+6=-3(x+6)
y+6=-3x-18
3x+y+24=0
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Find the estimates of x^2-x-2=3
Julli [10]

Answer:

x=\frac{1+\sqrt{21}}{2}\approx 2.79\\or\ x=\frac{1-\sqrt{21}}{2}\approx -1.79

Step-by-step explanation:

Given

Quadratic equation is

x^2-x-2=3\\x^2-x-5=0

Roots of the quadratic equation ax^2+bx+c=0 are

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\

So, for the given equation roots are

x=\frac{1\pm\sqrt{(-1)^2-4(1)(-5)}}{2\cdot 1}\\x=\frac{1\pm\sqrt{21}}{2}\\so, x=\frac{1+\sqrt{21}}{2}\approx 2.79\\or\ x=\frac{1-\sqrt{21}}{2}\approx -1.79

5 0
3 years ago
A description using numbers
HACTEHA [7]
Qi = letter D followed by letter A repeated i times

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6 0
4 years ago
How to find vertical and horizontal asymptotes of polynomials?
guajiro [1.7K]
Vertical asymptotes are when y tends to infinity, which in other words means you need a fraction where you're dividing by zero. So to find the vertical asymptotes, solve the denominator of the fraction and the solutions are the asymptotes since that is where it will be dividing by zero.

Horizontal asymptotes are the opposite and is where x tends to infinity -- This can be done by dividing through with the xs still there, since you are effectively just looking at multiples of infinity and infinity squared and so on. When you have an x to the power you can forget about all the other x's on the same half of the fraction, since infinity squared is infinitely bigger than infinity - yes it's abstract and a bit stupid I know.
If the degree of the polynomial on the denominator is larger than the numerator, there is an asymptote at y=0 (since the bottom becomes infinitely larger than the top). If it is lower than the numerator, you have to divide through by long division and you end up with an oblique asymptote i.e. an asymptote where the dotted line would follow a linear equation e.g. y=x

For example
f(x)= \frac{6x^2-3x+4}{2x^2-8}

The vertical asymptote can be found by solving 2x^2-8=0 i.e. x=+-2 so our vertical asymptotes are at 2 and -2.

The horizontal asymptote, think of all the x's as infinity. SInce there are x^2s, we dont need to worry about the numbers or the other x's
Therefore we are left with 6x^2/2x^2, which gives us 3. Therefore our horizontal asymptote would be at y=3.
7 0
3 years ago
Mario ate 1/8 of the pizza and his poodle ate 1/3 of the pizza. How much pizza is left?
levacccp [35]
The answer is 13/24 i dont know how you want it
7 0
3 years ago
Given that (–2, y) and (4, 6) are points on a line whose slope is-4/3 , find y.
bulgar [2K]

Answer:

The value of y is 14

Step-by-step explanation:

we know that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have the points

(-2, y)\ and\ (4, 6)

m=-\frac{4}{3}

substitute in the formula the given values

-\frac{4}{3}=\frac{6-y}{4+2}

solve for y

-\frac{4}{3}=\frac{6-y}{6}

Multiply by 6 both sides

-8=6-y

y=6+8=14

5 0
4 years ago
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