Answer:
what do you mean?
Step-by-step explanation:
Answer:
The Domain is where the line on your graph crosses the X axis.
The Range us where the line on your graph crosses the Y axis
And a arrow means it goes Into infinity
Step-by-step explanation:
Say you Have a line, it crosses the X axis at -3, your Domain would be -3!
Now say this line crosses the Y axis at -6, Your Range would be -6!
And now say if instead of the line ending at a dot after crossing -6 It has a arrow, that means you have infinity, Making your range instead of -6 it's be infinity! (If the arrow points up it's positive infinity, If the arrow points down it's negative infinity)
So for the first 2 numbers your answer would be [-3,-6] and in you have infinity itd be [-3, infinity) parenthesis isn't a error btw if you still don't get it I can just reply with a sheet I have on it
Answer:
∠1 ≅ ∠2 ⇒ proved down
Step-by-step explanation:
#12
In the given figure
∵ LJ // WK
∵ LP is a transversal
∵ ∠1 and ∠KWP are corresponding angles
∵ The corresponding angles are equal in measures
∴ m∠1 = m∠KWP
∴ ∠1 ≅ ∠KWP ⇒ (1)
∵ WK // AP
∵ WP is a transversal
∵ ∠KWP and ∠WPA are interior alternate angles
∵ The interior alternate angles are equal in measures
∴ m∠KWP = m∠WPA
∴ ∠KWP ≅ ∠WPA ⇒ (2)
→ From (1) and (2)
∵ ∠1 and ∠WPA are congruent to ∠KWP
∴ ∠1 and ∠WPA are congruent
∴ ∠1 ≅ ∠WPA ⇒ (3)
∵ WP // AG
∵ AP is a transversal
∵ ∠WPA and ∠2 are interior alternate angles
∵ The interior alternate angles are equal in measures
∴ m∠WPA = m∠2
∴ ∠WPA ≅ ∠2 ⇒ (4)
→ From (3) and (4)
∵ ∠1 and ∠2 are congruent to ∠WPA
∴ ∠1 and ∠2 are congruent
∴ ∠1 ≅ ∠2 ⇒ proved
Answer
Step-by-step explanation:
The remaining factor of x^2y - 2xy - 24y is (x - 6)(x + 4)
<h3>How to determine the remaining factor?</h3>
The expression is given as:
x^2y - 2xy - 24y
Factor out y from the expression
y(x^2 - 2x - 24)
Expand the equation
y(x^2 + 4x - 6x - 24)
Factorize
y(x - 6)(x + 4)
Hence, the remaining factor of x^2y - 2xy - 24y is (x - 6)(x + 4)
Read more about factored expression at:
brainly.com/question/19386208
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