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kvv77 [185]
3 years ago
10

During a catered lunch, an average of 4 cups of tea are poured per minute. The lunch will last 2 hours. How many gallons of tea

should the caterer bring if there are 16 cups in one gallon?
Mathematics
2 answers:
Veronika [31]3 years ago
8 0
4 cups every minute means 240 cups every hour:
4 X 60 (minutes per hour)

The lunch last 2 hours so if 240 cups is every hour then 480 cups would be for 2 hours.

Now covert 480 cups to gallons.  It takes 16 cups to make 1 gallon.  We would divide 480/16 = 30 gallons
ololo11 [35]3 years ago
6 0

Answer:

The answer is 30 gallons

Step-by-step explanation:

Idk I jsut guessed and got it right on edgunitiy

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Which two consecutive whole numbers would 341 be located?
marysya [2.9K]
The first number is 170
The second number is 171
Step-by-step explanation:
Let the first number be x^3 and the second number be x^3+1
The sum of the two is 341
X^3+x^3+1=341
2x^3+1=341
Substrate 1 from both sides
2x^3=341-1
8 0
4 years ago
Complete the equation <br> 9/4= ? ÷ by 4
Stells [14]

Answer:

9

Step-by-step explanation:

9/4 can be said as "9 divided by 4", so the ? is 9.

8 0
3 years ago
What is the prime factorization of 54?
seropon [69]
Actually none of them are the prime factors of 54.

A. indeed are factors, but neither of them are prime.
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So the prime factorization of 54 is 3*3*3*2
3 0
3 years ago
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Tickets to a play cost $10 for members and $24 for nonmembers. Write an expression to find the total cost of 4 non members ticke
Marianna [84]
This problem's quiet easy!

Cost for Members = $10 (x)
Cost for Non-Members = $ 24 (y)

2(x)+4(y) = Total Value. 
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Total Value = $ 116.


3 0
4 years ago
I need help please, I am so confused.​
vazorg [7]

Answer:

\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}

Step-by-step explanation:

x-intercepts are when the curve intercepts the x-axis, so when y =0.

Therefore, to find the x-intercepts, substitute y = 0 and solve for x.

The vertex is the turning point:  the minimum point of a parabola that opens upward, and the maximum point of the parabola that opens downward.  As a parabola is symmetrical, the x-coordinate of the vertex is the midpoint of the x-intercepts.

Equation:  y=x(x-2)

\implies x(x-2)=0

\implies x=0

\implies (x-2)=0 \implies x=2

Therefore, the x-intercepts are x = 0 and x = 2

The midpoint of the x-intercepts is x = 1, so the x-coordinate of the vertex is x = 1

Equation: y=(x-4)(x+5)

\implies (x-4)(x+5)=0

\implies (x-4)=0 \implies  x=4

\implies (x+5)=0 \implies x=-5

Therefore, the x-intercepts are x = -5 and x = 4

The midpoint of the x-intercepts is x = -0.5, so the x-coordinate of the vertex is x = -0.5

Equation: y=-5x(3-x)

\implies -5x(3-x)=0

\implies -5x=0 \implies x=0

\implies (3-x)=0 \implies x=3

Therefore, the x-intercepts are x = 0 and x = 3

The midpoint of the x-intercepts is x = 1.5, so the x-coordinate of the vertex is x = 1.5

\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}

4 0
2 years ago
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