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alexandr1967 [171]
3 years ago
11

Bob and Doug are both 100-meter sprinters. Bob's sprint time is normally distributed with a mean of 10.00 seconds and Doug's spr

int time is also normally distributed, but with a mean of 9.90 seconds. Both have the same standard deviation in sprint time σ. Assuming that Bob and Doug have independent sprint times, and given that there is a .95 chance that Doug beats Bob in any given race, find σ.
Mathematics
1 answer:
alexdok [17]3 years ago
3 0

Answer:

The standard deviation (σ) = 0.05

Step-by-step explanation:

The question is to find the standard deviation.

STEEP 1: FIND THE MEAN

(10+9.9) ÷ 2 = 9.95

STEP 2: SQUARE THE DIFFERENCE BETWEEN SPRINT TIME AND MEAN

10-9.95= 0.05

0.05^2 = 0.0025

9.9 - 9.95= -0.0025

-0.0025^2 = 0.0025

STEP 3: FIND THE VARIANCE

0.0025+0.0025= 0.005

0.005/2= 0.0025

STEP 4: FIND THE STANDARD DEVIATION (σ )

√variance

√0.0025 = 0.05

Therefore

σ = 0.05.

From the standard deviation, the percentage probability of the higher value to occurs is

0.05×100= 5%

That means Doug has 95%

And Bob has 5%

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(5x+2) and {3(x+14)} what is
Phoenix [80]

Answer:

Step-by-step explanation:

x=20

Reorder the terms:

(2 + 5x) = 3(x + 14)

Remove parenthesis around (2 + 5x)

2 + 5x = 3(x + 14)

Reorder the terms:

2 + 5x = 3(14 + x)

2 + 5x = (14 * 3 + x * 3)

2 + 5x = (42 + 3x)

Solving

2 + 5x = 42 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.

2 + 5x + -3x = 42 + 3x + -3x

Combine like terms: 5x + -3x = 2x

2 + 2x = 42 + 3x + -3x

Combine like terms: 3x + -3x = 0

2 + 2x = 42 + 0

2 + 2x = 42

Add '-2' to each side of the equation.

2 + -2 + 2x = 42 + -2

Combine like terms: 2 + -2 = 0

0 + 2x = 42 + -2

2x = 42 + -2

Combine like terms: 42 + -2 = 40

2x = 40

Divide each side by '2'.

x = 20

Simplifying

x = 20

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3 years ago
The sum of 3 fifteens and 4 twos
iogann1982 [59]
The sum of 3 fifteens and 4 twos will be 45 +8 = 53

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3 years ago
I am stuck between two
Marina86 [1]

Answer:

It's 14.

Step-by-step explanation:

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Answer:

The mean for Stem is 2.5

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2 years ago
A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life
alisha [4.7K]

Answer:

a)

The null hypothesis is H_0: \mu \leq 10

The alternative hypothesis is H_1: \mu > 10

b-1) The value of the test statistic is t = 1.86.

b-2) The p-value is of 0.0348.

Step-by-step explanation:

Question a:

Test if the battery life is more than twice of 5 hours:

Twice of 5 hours = 5*2 = 10 hours.

At the null hypothesis, we test if the battery life is of 10 hours or less, than is:

H_0: \mu \leq 10

At the alternative hypothesis, we test if the battery life is of more than 10 hours, that is:

H_1: \mu > 10

b-1. Calculate the value of the test statistic.

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

10 is tested at the null hypothesis:

This means that \mu = 10

In order to test the claim, a researcher samples 45 units of the new phone and finds that the sample battery life averages 10.5 hours with a sample standard deviation of 1.8 hours.

This means that n = 45, X = 10.5, s = 1.8

Then

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.5 - 10}{\frac{1.8}{\sqrt{45}}}

t = 1.86

The value of the test statistic is t = 1.86.

b-2. Find the p-value.

Testing if the mean is more than a value, so a right-tailed test.

Sample of 45, so 45 - 1 = 44 degrees of freedom.

Test statistic t = 1.86.

Using a t-distribution calculator, the p-value is of 0.0348.

5 0
2 years ago
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