8+g
that is the expressioin!!
Answer:
P = (18a+10b+13) cm
Step-by-step explanation:
Given that,
A triangle has the lengths of (10a+9) cm, (8a—3) cm and (10b+7) cm.
We need to find an expression that represents the perimeter of the triangle.
Perimeter = sum of all sides
P = (10a+9) + (8a-3) + (10b+7)
Taking like terms together,
P = (10a+8a)+10b+(9-3+7)
= 18a+10b+13
Hence, the epresssion for the perimeter is (18a+10b+13) cm.
B I’m guessing, never really worked with something like this before though
Exponential functions are related to logarithmic functions in that they are inverse functions. Exponential functions move quickly up towards a [y] infinity, bounded by a vertical asymptote (aka limit), whereas logarithmic functions start quick but then taper out towards an [x] infinity, bounded by a horizontal asymptote (aka limit).
If we use the natural logarithm (ln) as an example, the constant "e" is the base of ln, such that:
ln(x) = y, which is really stating that the base (assumed "e" even though not shown), that:

if we try to solve for y in this form it's nearly impossible, that's why we stick with ln(x) = y
but to find the inverse of the form:

switch the x and y, then solve for y:

So the exponential function is the inverse of the logarithmic one, f(x) = ln x
The fourth class ends at 12:30 pm
<em><u>Solution:</u></em>
Given that Harold has 4 classes each morning
Each class is 1 hour long, and there are 10 minutes between classes
The first class is at 8 A.M
<em><u>To find: Time at which fourth class ends</u></em>
Since each is 1 hour long and 10 minutes gap between classes
First class = 8 A.M to 9 A.M
Second class = 9:10 A.M to 10 : 10 AM
Third class = 10 : 20 AM to 11 : 20 AM
Fourth class = 11 : 30 AM to 12 : 30 PM
Thus the fourth class ends at 12:30 pm