Answer:
Neither
Step-by-step explanation:
First, you need to put your equations in y=mx+b form
Your first equation...
5x + 4y = 3
4y = 3-5x
y = -5/4x + 3/4
Your second equation...
5x-4y = -3
-4y = -5x -3
y = 5/4x + 3/4
The slopes aren't the same and are not reciprocals, so the answer would be neither.
Answer:
Sorry but your question is incomplete!
it's impossible to answer this question if we don't know the <u>total number of outcomes</u>
<em>I'm referring to writing the question instead of OCR-ing it</em>
Answer:
D) The third side could be 4 meters long.
Step-by-step explanation:
The third side of a triangle must be greater than the difference and less than the sum of the other two sides.
5-4=1
5+4=9
So the third side must be GREATER THAN 1 and LESS THAN 9. (1<x<9)
Therefore, the answer can't be A or C. The second one <em>could </em>be correct, depending on how much less than 4 it is. But the last one is definitely correct.
Answer:
Follows are the solution to the given points:
Step-by-step explanation:
Given value:
For point a:
Moment generating function of X=?
Using formula:
integrating the values by parts:
![u = x \\\\dv = e^{(t-1)x}\\\\dx =dx \\\\v= \frac{e^{(t-1)x}}{t-1}\\\\M(t) =[\frac{e^{(t-1)x}}{t-1}]^{-\infty}_{0} -\int^{\infty}_{0} \frac{e^{(t-1)x}}{t-1} \ dx\\\\](https://tex.z-dn.net/?f=u%20%3D%20x%20%5C%5C%5C%5Cdv%20%3D%20e%5E%7B%28t-1%29x%7D%5C%5C%5C%5Cdx%20%3Ddx%20%5C%5C%5C%5Cv%3D%20%5Cfrac%7Be%5E%7B%28t-1%29x%7D%7D%7Bt-1%7D%5C%5C%5C%5CM%28t%29%20%3D%5B%5Cfrac%7Be%5E%7B%28t-1%29x%7D%7D%7Bt-1%7D%5D%5E%7B-%5Cinfty%7D_%7B0%7D%20%20-%5Cint%5E%7B%5Cinfty%7D_%7B0%7D%20%5Cfrac%7Be%5E%7B%28t-1%29x%7D%7D%7Bt-1%7D%20%5C%20dx%5C%5C%5C%5C)
![= \frac{1}{t-1} (0) - [\frac{e^{(t-1)x}}{(t-1)^2}]^{\infty}_{0}\\\\=\frac{1}{(t-1)^2}(0-1)\\\\=\frac{1}{(t-1)^2}\\\\](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B1%7D%7Bt-1%7D%20%280%29%20-%20%5B%5Cfrac%7Be%5E%7B%28t-1%29x%7D%7D%7B%28t-1%29%5E2%7D%5D%5E%7B%5Cinfty%7D_%7B0%7D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B%28t-1%29%5E2%7D%280-1%29%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B%28t-1%29%5E2%7D%5C%5C%5C%5C)
Therefore, the moment value generating by the function is 
In point b:
Using formula:
form point (a):
Differentiating the value with respect of t
when 
