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Scilla [17]
3 years ago
15

Please help thanks!!

Mathematics
2 answers:
Pepsi [2]3 years ago
8 0
The answer is 1.) 6^1/6


The third root of something is the same as an exponent to the 1/3 power.

(When an exponent is a fraction, the numerator is powers and the denominator finds the root. For example: 3 to the power of 4/2 is multiplied by itself 4 times (81) then the denominator, 2, means we find the square root of it (9). 4/2=2, and 3 to the 2nd power is also 9.)

So that would be 6 to the 1/3 power, then you find the square root of that, so it's (6 to the 1/3 power) to the 1/2 power, and according to the Power Rule (a power on top of a power means you multiply the two powers), that would end up being 1/6.

\sqrt{  \sqrt[3]{6}  }  =  \sqrt{ {6}^{ \frac{1}{3} } }  = (6 { \frac{1}{3} })^{ \frac{1}{2} }  =  {6}^{ \frac{1}{3}  \times  \frac{1}{2} }  =  {6}^{ \frac{1}{6} }

ANTONII [103]3 years ago
8 0
The answer is number 1
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Answer:

34

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4 0
3 years ago
If you good with 7th grade math pls help
DochEvi [55]

289 196 248 379 319 276 198 349

(in order) 196, 198, 248, 276, 289, 319, 349, 379  there are eight numbers.

--------------------------------------------------------------------------------------

196, 198, 248, 276

since the median is between 198 and 248, we must add both numbers together and divide them by two:

(198 + 248) ÷ 2

= 446/2

<h2>= 223 (first quartile)</h2>

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since the median is between 319 and 349, we must add both numbers together and divide them by two:

(319 + 349) ÷ 2

= 668/2

<h2>= 334 (third quartile)</h2>

--------------------------------------------------------------------------------------

Interquartile range:

<h2>IQR: 334 - 223 = 111 </h2>

<em>I double-checked my answers btw</em>

3 0
3 years ago
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ValentinkaMS [17]
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Answer:

Step-by-step explanation:

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8 0
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Read 2 more answers
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Gekata [30.6K]

Answer:

3

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4 0
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