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Illusion [34]
3 years ago
5

HOW DO YOU DO THIS? PLEASE HELP

Mathematics
1 answer:
Savatey [412]3 years ago
8 0
I don’t see a picture is there one anyway
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You bought a two liter container of cooking oil for $2.50. What is the cost per liter?
bearhunter [10]

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$1.25

Step-by-step explanation:

$2.50 / 2 = $1.25 per liter

4 0
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Multiply -10(-7x² + 5x)​
tatiyna

Answer: 70x^2 -50x

Step-by-step explanation:

^ means exponent

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Hello I need help with my homework if someone could help me and explain to me how this works that would be great thank you
Tatiana [17]

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Step-by-step explanation:

5. 17.25-8.25= 9

6. 7+8=15

7. 2*8=16 or 2*9=18

7 0
3 years ago
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Katie wants to know how much she needs to deposit into a two year CD account in order to earn $100 in simple interest. The accou
sergey [27]

Answer:

To obtain $ 100 in simple interest with a rate of 1.5%, Katie must deposit $ 6,666.66.

Step-by-step explanation:

Given that Katie wants to know how much she needs to deposit into a two year CD account in order to earn $ 100 in simple interest, knowing that the account currently has a 1.5% interest rate, the following calculation must be performed:

X x 0.015 = 100

X = 100 / 0.015

X = 6,666.66

6,666.66 x 1.015 = 6,766.66

Thus, to obtain $ 100 in simple interest with a rate of 1.5%, Katie must deposit $ 6,666.66.

7 0
2 years ago
During the 7th examination of the Offspring cohort in the Framingham Heart Study, there were 1219 participants being treated for
AlexFokin [52]

Answer:

95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

Step-by-step explanation:

We are given that during the 7th examination of the Offspring cohort in the Framing ham Heart Study, there were 1219 participants being treated for hypertension and 2,313 who were not on treatment.

The sample proportion is :  \hat p = x/n = 1219/3532 = 0.345

Firstly, the pivotal quantity for 95% confidence interval for the proportion of the population is given by;

      P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion = 0.345

           n = sample of participants = 3532

           p = population proportion

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population​ proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                         significance are -1.96 & 1.96}

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u>= [\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

    = [ 0.345-1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } } , 0.345+1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } } ]

    = [0.3293 , 0.3607]

Hence, 95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

6 0
3 years ago
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