A^2-9a+20=a^2-5a-4a+20=(a^2-5a)+(-4a+20)
a^2-9a+20=a(a^2/a-5a/a)+(-4)(-4a/(-4)+20/(-4))
a^2-9a+20=a(a-5)-4(a-5)
a^2-9a+20=(a-5)[a(a-5)/(a-5)-4(a-5)/(a-5)]
a^2-9a+20=(a-5)(a-4)
Cory brings five 1-gallon jugs of juice.
5 jugs * 1 gallon per jug = 5 gallons of juice total
Knowing that the cups Cory is using to serve can hold 8 fluid ounces, we are asked to figure out how many cups Cory can serve.
1 gallon = 128 fluid ounces
5 gallons = x fluid ounces
Let's set up a proportional equation.
1/128 = 5/x
Now, we can use cross products to simplify and solve.
1 * x = 128 * 5
x = 640 fluid ounces.
Therefore, Cory has a total of 640 fluid ounces.
To find out how many cups he can serve, we need to divide the total amount of juice he has (640 oz) by the amount of juice in each cup (8 oz).
640 / 8 = 80
Thus, Cory can serve 80 cups of juice at parent night.
The answer is 7.57 of what they make for each year
Answer:
○ A. No, x = -6 is not a zero of the polynomial.
The quotient is x - 29, and the remainder is 234.
Step-by-step explanation:
[x - 3][x - 20] >> Factored Form
Obviously, this is not a zero. Now, to get the remainder, we have to plug in the vertical line of <em>x = -6</em> into its conjugate, meaning an expression with opposite signs, which is <em>x + 6</em>. This is the expression we divide the dividend by, so you will have this:
\frac{{x}^{2} - 23x - 60}{x + 6}
Since the divisor is in the form of <em>x - c</em>, using Synthetic Division, we get this:
x - 29 + \frac{234}{x + 6}
You see? You have <em>x - 29</em> in the quotient, and you have 234 as the numerator remainder.
I am joyous to assist you anytime.
For the first one the answer is yes
