Answer: 2 bags of soil
Step-by-step explanation:
Answer:cos( A + B ) = cosAcosB - sinAsinB ;
cos( A + B ) / ( cosAsinB ) = ( cosAcosB - sinAsinB ) / ( cosAsinB ) = ( cosAcosB ) / ( cosAsinB ) - ( sinAsinB ) / ( cosAsinB ) = cosB / sinB - sinA / cosA = cotB - tanA ;
tan²(x) - sin²(x) = sin²(x)/cos²(x) - sin²(x)
… = sin²(x) (1/cos²(x) - 1)
… = sin²(x) (sec²(x) - 1)
… = sin²(x) tan²(x)
Step-by-step explanation:
Answer:
Step-by-step explanation:
last one
Answer:
3
Step-by-step explanation:
3/3x + 1/x+4 = 10/7x
3/3x + 1/x+4 = 10/7x , x=0,x=-4
1/x + 1/x+4 = 10/7x
1/x + 1/x+4 - 10/7x = 0
7(x+4)+7x-10(x+4) / 7x*(x+4) = 0
7x+28+7x-10x-40 / 7x*(x+4) = 0
4x-12 / 7x*(x+4) = 0
4x-12=0
4x-=12
x=3,x=0,x=-4
x=3
Area of a rectangle = length (l) * width (w)
A = 30ft * 20ft
A = 600 sq ft
Now the width of a sidewalk that surroundeds it = 3 ft
so now the area of the rectangle with sidewalk= 30+3ft * 20+3ft
A = (33*23) ft
A = 759 sg ft
Area of the sidewalk = 759 - 600
A = 159 sq ft
