Answered already okay. GFY.
Answer:
23
Step-by-step explanation:
plug and chug: 5(4)+3=20+3=23
To solve for proportion we make use of the z statistic.
The procedure is to solve for the value of the z score and then locate for the
proportion using the standard distribution tables. The formula for z score is:
z = (X – μ) / σ
where X is the sample value, μ is the mean value and σ is
the standard deviation
when X = 70
z1 = (70 – 100) / 15 = -2
Using the standard distribution tables, proportion is P1
= 0.0228
when X = 130
z2 = (130 – 100) /15 = 2
Using the standard distribution tables, proportion is P2
= 0.9772
Therefore the proportion between X of 70 and 130 is:
P (70<X<130) = P2 – P1
P (70<X<130) = 0.9772 - 0.0228
P (70<X<130) = 0.9544
Therefore 0.9544 or 95.44% of the test takers scored
between 70 and 130.
Answer:
The player with the most runs had a rush of 1,240 yards
Step-by-step explanation:
In this question, we are asked to calculate the number of yards that was rushed by one of two person given their combined run and an extra information.
Firstly, let the person that had the smaller number of rush have a rush of x rushes. The second person has a rush of 4 times the other. This makes a number of 4x rushes
By adding both together, we have a total of 1550 yards
Mathematically, this means that x + 4x = 1550
5x = 1550
x = 1550/5 = 310 rushes
The second player had a rush of 4x and that is 4 * 310 = 1,240 rushes
