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AleksAgata [21]
3 years ago
6

Suppose A and B are independent events. If P(A)=0.2 and P(B)=0.6, what is P(A^B)?

Mathematics
2 answers:
Ainat [17]3 years ago
5 0

Answer: P(A\cap B)=0.12

Step-by-step explanation:

We know that if two events M and N are independent, then the probability of the intersection of the two events is given by :-

P(M\cap N)=P(M)\times P(N)

Given: The events A and B are independent .

Therefore, P(A\cap B)=P(A)\times P(B)

If P(A)=0.2 and P(B)=0.6

Then,

P(A\cap B)=0.2\times 0.6\\\\\Rightarrow P(A\cap B)=0.12

lawyer [7]3 years ago
3 0
OK so you want the probabilty of A and B occurring.  Independet event probabilities are multiplied so its 0.2 * 0.6 = 0.12

b
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