Answer:
Creo que necesitas crear una nueva cuenta en el Brainly español. Para encontrarlo, tal vez pueda buscar una pregunta aleatoria en Internet seguida de Brainly y, con suerte, encontrará la correcta. Luego crea una cuenta en ese Brainly. Al menos pienso cómo lo haces.
Hi there!
The correct answer is A. HTML.
HTML stands for Hypertext Markup Language which is used in nearly all websites and web-based programs. HTML acts as a structure for a website giving you the text, page titles, text-boxes, etc... HTML is also used along with the languages of Javascript, CSS, C++, and others. DO NOT confuse languages like Javascript and the rest with Markup Languages because they are not the same! Javascript, for example, is what is used to make websites more user-friendly and interactive. When you use Brainly, for example, and you hover over someone's name or picture and that box pops up that is Javascript at work and not HTML or any other Markup Language.
-<span>ASIAX </span><span> </span><span>Frequent Answerer</span>
Answer:
public class Main
{
public static void main(String[] args) {
char greekLetter = '^';
System.out.println(greekLetter);
}
}
Explanation:
Create a char variable called greekLetter and set it to the ^
Print the greekLetter to the screen
Answer:
t= 8.7*10⁻⁴ sec.
Explanation:
If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.
As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.
Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:
If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:
⇒ t = 8.7*10⁻⁴ sec.
Answer:
<em>Given Data:</em>
<em>myBytes BYTE 10h, 20h, 30h, 40h </em>
<em>myWords WORD 3 DUP(?), 2000h </em>
<em>myString BYTE "ABCDE"</em>
<em />
Based on the data that we are given we can conclude that:
(a). a. EAX = 1
b. EAX = 4
c. EAX = 4
d. EAX = 2
e. EAX = 4
f. EAX = 8
g. EAX = 5
