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mash [69]
2 years ago
9

What is a possible weakness of an expert-novice pair?

Computers and Technology
1 answer:
evablogger [386]2 years ago
5 0

Answer:

The novice will be overwhelmed by the expert and not offer suggestions.

The novice will be overwhelmed by the expert and not offer suggestions.

Explanation:

Got it right on edge 2022

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Create a Python program that asks the user in which direction to go? north, South East, or West?
QveST [7]

Answer:

huh

Explanation:

adsfghjkhgfdghjfghjkl

7 0
2 years ago
The steps for creating a newsletter are to ____.
leonid [27]

Answer:

C) Plan, write, format, and proofread

Explanation:

You need a plan for any professional newspaper. Proofreading is also a vital step in the process. You can only format what you've already written, so it has to be C.

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3 years ago
A ________ -tier design includes a middle layer between the client and server that processes the client requests and translates
Vanyuwa [196]

Answer:

Three.

Explanation:

5 0
3 years ago
Hello again, just need help debugging-I honestly have no idea how the "isSpace" etc methods work and I've tried various syntaxes
Julli [10]

import java.util.Scanner;

public class JavaApplication81 {

   

   public static void main(String[] args) {

       Scanner s = new Scanner(System.in);

       System.out.println("Input the string");

       String as = s.nextLine();

       int cons = 0;

       int a = 0;

       int e = 0;

       int i = 0;

       int o = 0;

       int u = 0;

       int space = 0;

       int punc = 0;

       char c;

       int misc = 0;

       String punctuation = ".!,?";

       String consonants = "bcdfghjklmnpqrstvwxyz";

       for (int k = 0; k < as.length(); k++){

           c = as.charAt(k);

       if (Character.isWhitespace(c)){

           space ++;

       }

       else if (punctuation.indexOf(c) != -1){

           punc++;

       }

       else if (consonants.indexOf(c) != -1){

           cons++;

       }

       else if (c == 'a'){

           a++;

       }

       else if(c == 'e'){

           e++;

       }

       else if (c == 'i'){

           i++;

       }

       else if (c == 'o'){

           o++;

       }

       else if (c == 'u'){

           u++;

       }

       else{

           misc++;

       }

       

   }

       System.out.println(a+" a's");

       System.out.println(e+" e's");

       System.out.println(i+" i's");

       System.out.println(o+" o's");

       System.out.println(u+" u's");

       System.out.println(space+" spaces");

   

       System.out.println(punc+" punctuations");

       System.out.println(cons+" consonants");

       System.out.println(misc+" misc. (uppercase vowels, etc.");

   }

   

}

This is one example of how it could be done.

5 0
2 years ago
3. Which property is used to select full Row of data grid view
Tju [1.3M]

Answer:

I think a is correct answer.

4 0
3 years ago
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