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3 years ago

How do you Simplify (3a^2)^3

1 answer:

4 0

When a number with an exponent is raised to an exponent, you multiply the two exponents together to get the combined exponent of the simplified version.
Let's take our exponents, 2 and 3, and multiply them.

2 x 3 = 6

Therefore we can apply the sixth power to 3a for our final answer of 3a⁶.

Hope this helped!

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How to solve 4/7y-2 = 3/7 + 3/14

lisabon 2012 [21]

Solution

1) Simplify $\frac{4}{7y}$ to $\frac{4y}{7}$
$\frac{4y}{7}$ −2= $\frac{3}{7}$ + $\frac{3}{14}$

2) Simplify $\frac{3}{7}$ + $\frac{3}{14}$ to 914
 $\frac{4y}{7}$ −2= $\frac{9}{14}$

3) Add 2 to both sides
 $\frac{4y}{7}$ = $\frac{9}{14}$ +2

4) Simplify $\frac{9}{14
}$ +2 to $\frac{37}{14}$
$\frac{4y}{7}$ = $\frac{37}{14}$

5) Multiply both sides by 7
4y= $\frac{37}{14}$ ×7

6) Simplify $\frac{37}{14}$ ×7 to $\frac{259}{14}$
$\frac{4y}{7}$ = $\frac{259}{14}$

7) Simplify $\frac{259}{14}$ to $\frac{37}{2}$
$\frac{4y}{7}$ = $\frac{37}{2}$

8) Divide both sides by 4
y= $\frac{37}{2}$ ×4

9) Simplify 2×4 to 8
y= $\frac{37}{8}$

Hope this helps

5 0

3 years ago

Rewrite in simplest terms: -8(7y-8)-3(7y-7)

AfilCa [17]

Answer:

−77y+85

I hope I helped!

7 0

3 years ago

Use the given equation to determine if the points in the brackets are on the graph

dmitriy555 [2]

The points in the brackets are on the graph are (0, 2) and (6, 10)

<h3>How to determine if the points in the brackets are on the graph?</h3>

The equation of the line is given as

4x - 3y = -6

The points are given as:

{(0,2),(1,3),(4,7),(6,10)}

Rewrite as

(x, y) = {(0,2),(1,3),(4,7),(6,10)}

Next, we substitute the x and y values in the equation 4x - 3y = -6

So, we have

(0, 2):

4(0) - 3(2) = -6

-6 = -6 ---- true

(1, 3):

4(1) - 3(3) = -6

-5 = -6 ---- false

(4, 7):

4(4) - 3(7) = -6

-5 = -6 ---- false

(6, 10):

4(6) - 3(10) = -6

-6 = -6 ---- true

Hence, the points in the brackets are on the graph are (0, 2) and (6, 10)

Read more about linear equations at:

brainly.com/question/2226590

#SPJ1

3 0

2 years ago

Determine the cross product b*a a=2i+2j-5k b=6i-j+2k

Misha Larkins [42]

Recall the definition of the cross product:

i x i = j x j = k x k = 0

i x j = k

j x k = i

k x i = j

The cross product is antisymmetric, or anticommutative, meaning that for any vectors u and v, we have u x v = - (v x u).

It's also distributive, so for any vectors u, v, and w, we have (u + v) x w = (u x w) + (v x w).

Taking all of these properties together, we get

b x a = (6i - j + 2k) x (2i + 2j - 5k)

b x a = 12 (i x i) - 2 (j x i) + 4 (k x i)

............. + 12 (i x j) - 2 (j x j) + 4 (k x j)

............. - 30 (i x k) + 5 (j x k) - 10 (k x k)

b x a = 1 (j x k) + 34 (k x i) + 14 (i x j)

b x a = i + 34j + 14k

5 0

3 years ago

What is the pattern of odd and even products in each row

andrew11 [14]

There isn't a picture of a pattern to go by.

5 0

3 years ago