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2 years ago

1/3t + 3/4 = 2/4 -t solve

1 answer:

4 0

Okay so I am going to summarize the work out process because its a lot to

Here we go

1/3 (t) + 3/4 - 2/4 - t = ?

1/2 (simplify )

(1/3 (T)+3/4 - 1/2 - (t) = ?

t (2) / 2

1 - 2(t) / 2 = ?

3/4 (simplify this )

1/3(t)+ 3/4 - [1 - 2(t) / 2 = ?

1/3 (this is re last one you have to simplify)

L (Denominator): 3

R (Denominator): 4

L: [L.C.M] : 4

R: [L.C.M] : 3

Basically , we just switched the dominators around

So, Therefore The of t is -3/16

T = -3/16

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If five times the successor of a number is added to an original number the sum is 83

Alexus [3.1K]

Answer:

Let the original number be x

Successor is defined as the number which comes immediately after a particular number.

also, the successor of a whole number is the number obtained by adding 1 to that number.

Then, the successor of a number x is, x+1

As per the given condition :

we have;

$5(x+1)+x =83$

Using distributive property on LHS (i.e, $a\cdot(b+c)=a\cdot b+a\cdot c$ )

Then, we have

5x+5+x=83

Combine like terms;

6x+5=83

Subtract 5 from both the sides we get;

6x+5-5=83-5

Simplify:

6x=78

Divide both side by 6,

$\frac{6x}{6} =\frac{78}{6}$

Simplify:

x =13

Therefore, the original number x is, 13

8 0

2 years ago

On a 40 question test students gain 6 points for each correct answer and lose 0.5 points on each incorrect answer. If everyone r

juin [17]

Answer:

$\text{r}=5.5\text{c}-20$

Step-by-step explanation:

GIVEN: On a $40$ question test students gain $6$ points for each correct answer and lose $0.5$ points on each incorrect answer. If everyone required to give an answer to each question.

TO FIND: the formulas that describes how a student's raw score, r, depends on the number of correct answers he or she provided, c.

SOLUTION:

Total number of incorrect questions $=40-\text{c}$

Total marks deducted due to incorrect question $=(40-\text{c})\times0.5=20-0.5\text{c}$

Total correct questions $=\text{c}$

Total marks scored $=6\text{c}$

Total raw marks $\text{r}=\text{total marks gained}-\text{total marks deducted}$

$\text{r}=6\text{c}-(20-0.5\text{c})$

$\text{r}=5.5\text{c}-20$

ormulas that describes how a student's raw score, r, depends on the number of correct answers he or she provided, c is $\text{r}=5.5\text{c}-20$

7 0

2 years ago

Look at the two equations:

Dvinal [7]

Answer:

$- 3x + 6 = 21$

$- 3x = 21 - 6$

$- 3x = 18$

$- 3x \div - 3 = 18 \div - 3$

$x = - 6$

$- 3x + 6 < 21$

$- 3x < 21 + 6$

$- 3x < 27$

$- 3x \div - 3 < 27 \div - 3$

$x > - 9$

8 0

2 years ago

The mean of a population being sampled is 64, and and the standard deviation is 6. If the sample size is 50, the standard error

Fiesta28 [93]

Given:
mean = 64
standard deviation = 6
sample size = 50

Standard error of the sample mean = standard deviation / √sample size

Standard error = 6 / √50 = 6/7.07 = 0.85

6 0

2 years ago

Find a formula for the nth partial sum Sn of the following series. If the series is finite, determine the sum. If the series is

Xelga [282]

Answer:

Step-by-step explanation:

put i=1,2,...,n

$\frac{1}{5}-\frac{1}{6}\\\frac{1}{6}-\frac{1}{7}\\\frac{1}{7}-\frac{1}{8}\\..............\\................\\................\\\frac{1}{n-1}-\frac{1}{n}adding ~vertically~downwards\\S_{n}=\frac{1}{5}-\frac{1}{n}$

5 0

3 years ago