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LenaWriter [7]
3 years ago
11

Solve the inequality n + 20 < -42, and write the solution in interval notation.

Mathematics
1 answer:
Firdavs [7]3 years ago
4 0

Answer:

Step-by-step explanation:

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Lisa went on a 52 km hike. She divided the distance traveled evenly over 4 days.
grandymaker [24]
she walked 12 and a half meter every day 12.5
8 0
3 years ago
The base of the triangle is 5<img src="https://tex.z-dn.net/?f=%5Csqrt%7B3%7D" id="TexFormula1" title="\sqrt{3}" alt="\sqrt{3}"
Vsevolod [243]

Answer:

yes you are absolutely right

it will be the answer

4 0
3 years ago
Rewrite the function by completing the square. 4x^2-4x+1=0
andrey2020 [161]

Do in <u>completing the square method.</u>

{4x}^{2}  - 4x + 1 = 0 \\ 4x^{2}-4x=-1  \\ \frac{4x^{2}-4x}{4}=\frac{-1}{4}  \\ x^{2}+\frac{-4}{4}x=\frac{-1}{4}  \\ x^{2}-x=\frac{-1}{4}  \\ x^{2}-x+\left(-\frac{1}{2}\right)^{2}=-\frac{1}{4}+\left(-\frac{1}{2}\right)^{2}  \\ x^{2}-x+\frac{1}{4}=\frac{-1+1}{4}  \\ x^{2}-x+\frac{1}{4}=0  \\ \left(x-\frac{1}{2}\right)^{2}=0  \\ \sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{0}

Now simplify.

x-\frac{1}{2}=0 \\  x-\frac{1}{2}=0  \\  \\  \rightarrow \: x=\frac{1}{2}  \\  \rightarrow \: x=\frac{1}{2}

So, answer is..

\boxed{x=\frac{1}{2} }

Now <u>rewrite</u> the equation.

4 x ^ { 2 } - 4 x + 1 = 0 \\  \boxed{4\times \left(\frac{1}{4}\right)-4\times \left(\frac{1}{2}\right)+1=0  }

<u>Verification :-</u>

4 x ^ { 2 } - 4 x + 1 = 0 \\ 4\times \left(\frac{1}{4}\right)-4\times \left(\frac{1}{2}\right)+1=0  \\ 1-4\times \left(\frac{1}{2}\right)+1=0  \\ 1-\frac{4}{2}+1=0  \\ 1-2+1=0  \\ -1+1=0  \\ \underline{ 0 = 0} \:  \\  \dashrightarrow \text{true}

3 0
3 years ago
(1 point) For the equation given below, evaluate ′ at the point (−1,2). (5−)^4+4^3=2433. ′ at (−1,2) =
ryzh [129]

Answer:

\dfrac{343}{71}

Step-by-step explanation:

Given the equation

(5x-y)^4+4y^3=2433

Find the derivative:

((5x-y)^4+4y^3)'=(2433)'\\ \\4(5x-y)^3\cdot (5x-y)'+4\cdot 3y^2\cdot y'=0\\ \\4(5x-y)^3\cdot (5-y')+12y^2y'=0

Substitute

x=-1\\ \\y=2,

then

4(5\cdot (-1)-2)^3\cdot (5-y')+12\cdot 2^2\cdot y'=0\\ \\4(-5-2)^3(5-y')+48y'=0\\ \\4\cdot (-7)^3\cdot (5-y')+48y'=0\\ \\-1,372(5-y')+48y'=0\\ \\-6,860+1,372y'+48y'=0\\ \\1,420y'=6,860\\ \\y'=\dfrac{6,860}{1,420}=\dfrac{686}{142}=\dfrac{343}{71}

6 0
3 years ago
1) 9x-3y+7-4x+y-3 simplified
Serjik [45]

Answer:

1. 6+3+3

2. 15-5+4

3.4+2

5 0
3 years ago
Read 2 more answers
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