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PSYCHO15rus [73]
3 years ago
11

What is 4/1 times 2=to

Mathematics
1 answer:
taurus [48]3 years ago
3 0
Any expression divided by remains the same, Multiply the numbers, answer is 8
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Round 299 to the nearest hundred. Enter your answer in the box below.
Troyanec [42]

Answer:

300

Step-by-step explanation:

hundreds  tens  ones

2                   9      9

We look at the tens

It is 5 or higher so we round up the hundreds place

2 becomes 3

300

7 0
3 years ago
Read 2 more answers
HELP PLS DUE TODAY NO CAP THIS TIME NO JOKE!!!!!!!!!!!!!
dedylja [7]

Answer:

what? were is the problem...

Step-by-step explanation:

3 0
3 years ago
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The painting shown on the right has an area of 300 in^2. what is the value of x?
Nataly [62]

Answer: X = 10.20240940...

Step-by-step explanation:

x(2x + 9) = 2x^2 + 9x

2x^2 + 9x = 300

- 300 ON BOTH SIDES

2x^2 + 9x - 300 = 0

SOLVE USING THE QUADRATIC FORMULA

x = -b +/- all root (b)^2 - 4(a)(c) All over 2(a)

When all the values are plugged in:

When using "+" in the equation you should get:

x = 10.20240940…

When using "-" in the equation you should get:

x = −14.70240940…

Now.. you CANNOT have a negative length, so you cross of the negative value leaving you one value for x which is 10.20240940...

YOUR ANSWER IS:    x   =  10.20240940...

4 0
2 years ago
In the figure, AngleRQS Is-congruent-to AngleQLK. 3 lines are shown. Lines S P and K N are parallel. Line R M intersects line S
stepan [7]

Answer:

x=108

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

m∠RQS≅m∠QLK -----> by corresponding angles

m∠KLM+m∠QLK=180° -----> by supplementary angles (consecutive interior angles)

we have that

m∠RQS=x° ----> given problem

so

m∠QLX=x°

m∠KLM=(x-36)° ----> given problem

substitute

(x-36)\°+x\°=180\°\\2x=180+36\\2x=216\\x=108

3 0
3 years ago
Read 2 more answers
What is the length of the altitude of the equilateral triangle below?
Mazyrski [523]

ANSWER

The length of the altitude is 3\sqrt{3} units


<u>EXPLANATION</u>

The altitude of a triangle is the vertical height of the triangle.


From the diagram the altitude is a


Method 1: We can use Pythagoras theorem to find a


6^2=a^2+3^2


6^2-3^2=a^2


36-9=a^2


27=a^2


We take the square root of both sides,

\sqrt{27}=a


\sqrt{9\times3}=a


\sqrt{9} \times \sqrt{3}=a


3\sqrt{3}=a


Method 2 Using Trigonometry

sin(60\degree)=\frac{a}{6}

6sin(60\degree)=a


a=6\times \frac{\sqrt{3}} {2}


a=3\sqrt{3}






6 0
3 years ago
Read 2 more answers
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