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Dima020 [189]
4 years ago
12

Determining rational and irrational numbers quick 25 pts

Mathematics
2 answers:
Arlecino [84]4 years ago
4 0
11/15 + 7 ⇒ rational ⇒ the sum of two rationals is always rational

√14+13 ⇒ irrational ⇒ the sum of a rational and an irrational  is always irrational

30×√6 ⇒ irrational ⇒ the product of a nonzero rational and an irrational  is always irrational

11/12 × 7/15 ⇒ rational ⇒ the product of two rationals is always rational
Lina20 [59]4 years ago
4 0

Answer:

11/15 + 7 : rational 


√14+13 : irrational 


30×√6 : irrational 


11/12 × 7/15 : rational 


Hope it helps!


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9. Find the Highest Common Factor of
netineya [11]
C. 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, and 60

1,000: 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 125, 200, 250, 500, 1000

Now we find the common numbers. One doesn’t count as when multiplied later on, it will not change anything.

60: 2, 4, 5, 10, 20

1,000: 2, 4, 5, 10, 20

The highest common factor is 20 because it’s, well, the highest number.

D. Do the same thing for D.

24: 1, 2, 3, 4, 6, 8, 12, 24

880: 1, 2, 4, 5, 8, 10, 11, 16, 20, 22, 40, 44, 55, 80, 88, 110, 176, 220, 440, 880

20 and 880: 2, 4, 8

8 is the Highest Common Factor.

E. Do the same thing with E.

90: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

1,000: 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 125, 200, 250, 500, 1000

90 and 1000: 2, 5, 10

10 is the Highest Common Factor.

3 0
3 years ago
Read 2 more answers
There are 15 candidates for 4 job positions.
Veronika [31]

Answer:

32760 ways

Step-by-step explanation:

Given

Number of Candidates = 15

Job Positions = 4

Required:

Number of outcomes

This question represent selection; i.e. selecting candidates for job positions;

This question can be solved in any of the following two ways

Method 1.

The first candidate can be chosen from any of the 15 candidates

The second candidate can be chosen from any of the remaining 14 candidates

The third candidate can be chosen from any of the remaining 13 candidates

The fourth candidate can be chosen from any of the remaining 12 candidates

Total Possible Selection = 15 * 14 * 13 * 12

<em>Total Possible Selection = 32760 ways</em>

<em></em>

Method 2:

This can be solved using permutation method which goes thus;

nPr = \frac{n!}{(n-r)!}

Where n = 15 and r = 4

So;

nPr = \frac{n!}{(n-r)!} becomes

15P4 = \frac{15!}{(15-4)!}

15P4 = \frac{15!}{11!}

15P4 = \frac{15*14*13*12*11!}{11!}

15P4 = 15*14*13*12

15C4 = 32760

<em>Hence, there are 32760 ways</em>

8 0
4 years ago
Please find the domain and range!
SpyIntel [72]

Answer:

Domain: {-2, -3, 6, 8, 10}

Range: {-5, 1, 7, 9}

Step-by-step explanation:

Given:

{(6, -5), (-2, 9), (-3, 1), (10, 7), (8, 9)}

✔️Domain:

This includes all the set of the x-values that are in the relation. This includes, 6, -2, -3, 10, and 8.

Thus, the domain can be represented as:

{-2, -3, 6, 8, 10}

✔️Range:

This includes all corresponding y-values in the relation. They are, -5, 1, 7, and 9.

Range can be represented as:

{-5, 1, 7, 9}

3 0
3 years ago
The freezing point of water is 32°F. When water is at or below this temperature, it is in solid form. Which statements are true
mamaluj [8]

Answer:

The number 32 is part of the solution set

The circle on the graph is closed

The arrow on the graph points to the left

Step-by-step explanation:

The number 32 is part of the solution because it said that water freezes at 32 degrees when it is at or below 32

The circle on the graph is closed because 32 is part of the answer , when the solution is showed then the circle is closed.

Last but not least the arrow on the graph points left because water freezes when it is at 32 or below 32 degrees, so when it points left the numbers become lower.

Hope this helped! :)

8 0
3 years ago
Read 2 more answers
Let y be a random variable with p(y) given in the accompanying table. find e(y ), e(1/y ), e(y 2 − 1), and v(y ). y 1 2 3 4 p(y)
Studentka2010 [4]
<span>E[Y] = 0.4·1 + 0.3·2 + 0.2·3 + 0.1·4 = 2 E[1/Y] =0.4·1/1 + 0.3·1/2 + 0.2·1/3 + 0.1·1/4 = 0.4 + 0.15 + 0.0666 + 0.025?0.64 V[Y] =E[Y2]-E[Y]2= (0.4)·12+(0.3)·22+(0.2)·32+(0.1)·42-22= 0.4+1.2+1.8+1.6-4= 5-4 = 1</span>
8 0
4 years ago
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