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Nat2105 [25]
2 years ago
6

Hennietta has a box of fruit with a mass of 88 dekameters. What is the weight of the vid of fruit in kilograms

Mathematics
2 answers:
vagabundo [1.1K]2 years ago
8 0

Answer: 0.88 kilometers

iogann1982 [59]2 years ago
4 0

Answer:

.88 is the might be it i think

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What is the interquartile range of the following data set 2, 5, 9, 11, 18,30, 42, 55, 58, 73, 81
In-s [12.5K]

Answer:

4.2/5. 4.

Step-by-step explanation:

4 0
3 years ago
Help!<br><br> <img src="https://tex.z-dn.net/?f=%5Csf%20%5Csqrt%7Bx-2%7D-x%3D-2" id="TexFormula1" title="\sf \sqrt{x-2}-x=-2" al
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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Let's solve for x :

  • \sqrt{x - 2}  - x =  - 2

  • \sqrt{x - 2}  = x - 2

  • 1 =  \dfrac{x - 2}{ \sqrt{x - 2} }

  • 1 =  \sqrt{x - 2}

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  • x = 3
4 0
2 years ago
Find the possible subsets of A = {a,b}​
Karolina [17]

Answer:

Step-by-step explanation:

Subset of A = { {} , {a} , {b}, {a.b} }

7 0
3 years ago
A deck of ordinary cards is shuffled and 13 cards are dealt. What is the probability that the last card dealt is an ace?
alexandr1967 [171]

Answer:

The probability that the last card dealt is an ace is \frac{1}{13}.

Step-by-step explanation:

Given : A deck of ordinary cards is shuffled and 13 cards are dealt.

To find : What is the probability that the last card dealt is an ace?

Solution :

There are total 52 cards.

The total arrangement of cards is 52!.

There is 4 ace cards in total.

Arrangement for containing ace as the 13th card is 4\times 51!.

The probability that the last card dealt is an ace is

P=\frac{4\times 51!}{52!}

P=\frac{4\times 51!}{52\times 51!}

P=\frac{4}{52}

P=\frac{1}{13}

Therefore, the probability that the last card dealt is an ace is \frac{1}{13}.

4 0
3 years ago
Khan khan khan khan
Ber [7]

Answer:

11

Step-by-step explanation:

it says motor cycles combined with garbage so add both of them then subtract that from the bull dosers

motor =18

garbage=4

18+4=22

bulldosers=11

22-11= 11 more

5 0
3 years ago
Read 2 more answers
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