F(gx)
f(-x-4) = 2(-x-4) + 3
F(-x-4)= -2x-8+3
F(-x-4)= -2x-5
G(fx)
G(2x+3)= -(2x+3) -4
G(2x+3)= -2x-3-4
G(2x+3)= -2x-7
F(hx)
F(x^2)=2x^2+3
H(fx)
H(2x+3)= (2x+3)^2
H(2x+3)= (2x^2) + 2(2x)(3)+3^2
H(2x+3)= 4x^2+12x+9
[I think I messed up with the last one. I didn’t know how to get the correct answer for that. Sorry ]
Answer: nvm I got it wrong sorry for taking up an answer spot!
Step-by-step explanation:
How much of each solution should the teacher mix together to get 105 ML of 60% sugar solution for an experiment?
1. Look at how 60% is closer to the solution of lower concentration (50%). You can deduce that you will be mixing a higher volume of the 50% solution.
2. All 4 answers add up to 105ml.
3. The intuitive answer is the first option:
70 ML of the 50% solution and 35 ML of the 80% solution
4. Let's check whether point 3 is true.
70ml/105ml X 0.5 + 35ml/105ml X 0.8 = (35 + 28)/105= 63/105= 60% / 105 ml = 105ml of 60% sugar solution
Just put in the x values for example
First one x = 1
y = 2(1) + 5
y= 7
I’ll tell u all the answers here in order:
7
9
15
19
Answer:
Your answer is 150 units!
