Point slope form = y - b= m ( x - a )
where y and x stay the same
m is the slope
and (a, b) (any coordinate on the graph)
based on the point (5, -7)
Y - (-7) = -3 (x - 5)
however, the - cancels out the negative 7 making I positive
Y + 7 = -3(x - 5)
He can only go as low as $500
Answer:
It will take 10 hours.
Step-by-step explanation:
We know distance = rate * time
Sally's rate = 55
Jim's rate = 65
We want Jim to be 100 miles ahead of Sally
The time will always be the same.
d =Sally's distance
Sally
d = 55t
Jim
d+100 = 65 t
We know have 2 equations with 2 unknowns. Substitute d= 55t into Jim's equations
55t + 100 = 65t
Subtract 55t from both sides.
55t-55t + 100 = 65t-55t
100 = 10t
divide each side by 10
100/10 = 10t/10
10 = t
The numerical sum of the degree measures of m ∠DEA and m ∠AEF and m ∠DEF is 360°; The numerical measures of the angles is,
m ∠DEA = 56°
m ∠AEF = 158°
m ∠DEF = 146°
Based on the given data,
m ∠DEA= x + 30,
m ∠AEF= x + 132, and
m ∠DEF= 146 degrees
If the sum of two linear angles is 360° then, they are known as supplementary angles.
∠A + ∠B + ∠C = 360°, (∠A and ∠B and ∠C are linear angles.)
So,
We can write,
m ∠AEF + m ∠DEA + m ∠DEF = 360°
( x + 132) + (x + 30) + 146 = 360°
x + 30 + x + 132 + 146 = 360°
2x + 308 = 360°
2x = 360° - 308
x = 52/2
x =26
Now, we will substitute the value of x = 26° in the ∠DEA and ∠AEF, hence we get:
m ∠DEA = x + 30
m ∠DEA = 26 + 30
m ∠DEA = 56 degrees
Also,
m ∠AEF = x + 132
m ∠AEF = 26 + 132
m ∠AEF = 158
Hence,
m ∠DEA + m ∠AEF + m ∠DEF = 360°
56 + 158 + 146 = 360°
360° = 360°
Therefore,
Therefore, the numerical sum of the degree measures of m ∠DEA and m ∠AEF and m ∠DEF is 360°; The numerical measures of the angles is,
m ∠DEA = 56°
m ∠AEF = 158°
m ∠DEF = 146°
To learn more about information visit Supplementary angles :
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Answer:-69
Step-by-step explanation:
The sum of +3 & (6-0)=9
-60-(+9)=-69
