Answer:
=IF(B2>=23,"Yes","No")
Explanation:
Given
Name = Kay Colbert
The Name column can't be used to determine the eligibility of a student to the transport.
What is needed is the corresponding age column of Kay's age.
Assume that the age column is B2 and the result column is C2 (See Attachment)
Enter the following in C2
=IF(B2>=23,"Yes","No")
This will return "Yes" without the quotes in cell C2 if B2 is greater than 23
Else, it'll return "No" without the quotes.
To drag the formula to other column, follow the instructions below
Select cell C2.
Rest your cursor in the lower-right corner so that it turns into a plus sign (+), like this:
Drag the fill handle downwards
A cryptocurrency is a digital asset designed to work as a medium of exchange that uses strong cryptography to secure financial transactions, control the creation of additional units, and verify the transfer of assets.
The answer to this question is the PET scan. Positron
Emission Tomography or PET scan is an imaging test that checks and trace for
diseases in the body. This also shows how the body organs is functioning /
working. The doctor can evaluate the function of the patients body by the 3D
color images produced by the PET Scan.
Answer:
C. Mean
Explanation:
Mean = (∑
)/N
Median = central values when data is sorted
Mode = most repeated value
Standard deviation = 
In standard deviation, formula you may see that deviation is being calculated from the mean (central location). But here we take square of the value before adding all of them.
But if we just take 
, it would be equal to zero.
<u>EXAMPLE</u>
Take 4, 9, 5 as data
mean = (4+9+5)/3 = 18/3 = 6
sum of deviations from mean = (4-6)+(9-6)+(5-6) = (-2)+(3)+(-1) = 0
Answer:
Explanation:
The following Python program uses a combination of dictionary, list, regex, and loops to accomplish what was requested. The function takes a file name as input, reads the file, and saves the individual words in a list. Then it loops through the list, adding each word into a dictionary with the number of times it appears. If the word is already in the dictionary it adds 1 to its count value. The program was tested with a file named great_expectations.txt and the output can be seen below.
import re
def wordCount(fileName):
file = open(fileName, 'r')
wordList = file.read().lower()
wordList = re.split('\s', wordList)
wordDict = {}
for word in wordList:
if word in wordDict:
wordDict[word] = wordDict.get(word) + 1
else:
wordDict[word] = 1
print(wordDict)
wordCount('great_expectations.txt')
