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3 years ago

**At noon the minute and the hour hands overlap. When will it happen next?

Mathematics

1 answer:

Svetllana [295]3 years ago

7 0

Answer: At 01:05 p.m. it will overlap again.

Explanation:

Since there are 22 times in a day the minute and the hour hands overlap.

During the first half of the day , it overlaps 11 times and during the rest of the day it overlap 11 more times.

At noon, the minute and the hour hands overlap and after that it will happen at 01:05 p.m.

Since the minute hand completes a full circle in one hour, so it forms 6 degrees per minute .

So, at 01:05 p.m. it will overlap again.

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sp2606 [1]

Answer:

Step-by-step explanation:

Probability is the likelihood of an event taking place.

-Given there are 95 white and 5 blue pieces, the total number of papers is 100.

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Hence, the theoretical probability that a blind-folded person draws a blue piece of paper on the first attempt is 0.05 or 5%

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3 years ago

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3 years ago

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MrRa [10]

<h3>Answer:</h3>

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<h3>Step-by-step explanation:</h3>

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But when you multiply the new lengths together, the area would be of 4 times more.

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(Scale Factor of 2) 4 * 4 = 16

So when the scale factor is made, the area would be squared to the multiple that you scaled it by.

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<em>9 and 225 would be the square root in these problems.</em>

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3 years ago

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Kruka [31]

Answer:

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Step-by-step explanation:

Hope this helps:)

8 0

2 years ago

The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00. Assu

m_a_m_a [10]

Answer: 0.0170

Step-by-step explanation:

Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.

i.e. $\mu=23.50$

$\sigma=5$

We assume the distribution of amounts purchased follows the normal distribution.

Sample size : n=50

Let $\overline{x}$ be the sample mean.

Formula : $z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

Then, the probability that the sample mean is at least $25.00 will be :-

$P(\overline{x}\geq\25.00)=P(\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\geq\dfrac{25-23.50}{\dfrac{5}{\sqrt{50}}})\\\\=P(z\geq2.12)\\\\=1-P(z$

Hence, the likelihood the sample mean is at least $25.00= 0.0170

5 0

3 years ago