A. The angles at the intersection of the two lines can be proven to be congruent and complementary . so they meet at a right angle and the lines are perpendicular.
<u>Step-by-step explanation:</u>
In above question, In order to find whether AB ⊥ CD, Using compass construction & rounder , keep the tip at A and cut arcs at line CD . Follow the same process again with tip at B and cut arcs at line CD . Do this both sides of Line CD i.e. on left side of AB & on right side of AB. Now, join the intersection points of both side arcs which are intersecting each other. Now, to prove both are right angle to each other i.e. AB ⊥ CD , can be done by proving congruent and complementary , so they meet at a right angle and Hence , the lines are perpendicular i.e. AB is inclined to CD at angle of 90°.
550+40W=S is the equation and after 11 weeks, she would have $990
Answer:
KF = 35
Step-by-step explanation:
Since it's a line with K in the middle, we know that the distance SF is the same as SK + KF.
(Start at S, first go to K, then continue to F. You've traveled the same distance as from S to F.)
SF = SK + KF
Let's put in the values we got.
5x + 2 = 27 + (3x -1)
Opening the parenthesis.
5x + 2 = 27 + 3x - 1
5x + 2 = 26 + 3x
Now let's subtract 3x from both sides.
2x + 2 = 26
Now, subtract 2 from both sides.
2x = 24
If we divide by 2...
x = 12
We know that...
KF = 3x -1
Since x is 12, let's put that in.
KF = 3 * 12 - 1 = 36 - 1 = 35
Answer: KF is 35 !
Answer:
The answer is 4x
Step-by-step explanation: This is because all of the domains are usually in the dominant variable which in most cases is x
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I think the answer is <span>C) The number of circles on a page is 6 times the number of circles on the previous page.
</span>If we plugged in p = 1, then it leads to c(p) = 6
This is saying "on page 1 (p = 1), the number of circles on this page is 6"
<span>ie, "There are 6 circles on page 1"</span><span>
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