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Degger [83]
3 years ago
12

Which statement best compares the graphs of f(x)=[x] and f(x)=[x]? The two graphs are exactly the same. The open and closed circ

les are reversed. The open and closed circles are reversed, and the graph of f(x)=[x] shifts up. The open and closed circles are the same, but the graph of f(x)=[x] shifts up.

Mathematics
2 answers:
Artyom0805 [142]3 years ago
7 0
Unless, you have a typo the graphs are exactly the same. You have the same function listed and the equation is exactly the same. You have f(x) = [x] for both equations.
timurjin [86]3 years ago
6 0

Answer:

the open and closed circles are reversed and the graph of f(x)=ceil(x) i. e. least integer function shifts up.

Step-by-step explanation:

the explanation to this question could be clearly seen from the graph of these two functions.

as  for     0 ≤x<1 the floor function takes the value 0 everywhere and it has closed brackets at 0 and open brackets at 1, while for   0<x≤1 the ceiling function takes the value 1 and it has open brackets at 0 and closed brackets at 1 similarly the graph could be extended in the whole real line.


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Lucy is a dress maker. She sews \dfrac47
Strike441 [17]

Answer:

\frac{16}{21} dresses

Step-by-step explanation:

We are given that

Lucy sews dress in 3/4 hours=\frac{4}{7} of dress

Lucy sews at constant rate.

We have to find the number of dresses sewed by Lucy in hour.

To find number of dress sewed by Lucy in 1 hour we will use unitary method.

By using unitary method

Lucy sews in 3/4 hours=\frac{4}{7} dress

Lucy sews in 1 hour=\frac{\frac{4}{7}}{\frac{3}{4}}

Lucy sews in 1 hour=\frac{4}{7}\times \frac{4}{3}

Lucy sews in 1 hour=\frac{16}{21} dresses

Hence, Lucy sews \frac{16}{21} dresses in 1 hour.

5 0
3 years ago
Can someone help me pls?
LiRa [457]

Answer:

x = 17.2

Step-by-step explanation:

cos 35 = x/21

0.8192(21) = x

x = 17.2

5 0
3 years ago
How many pounds of nuts worth $1.10 per pound must be mixed with 36 pounds of candy worth $1.60 per pound to produce a party mix
Tanzania [10]
\bf \begin{array}{lccclll}&#10;&amount&price&\textit{total price}\\&#10;&-----&-----&-----\\&#10;\textit{nuts \$1.10/lb}&x&1.10&1.10x\\&#10;\textit{candy \$1.60/lb}&36&1.6&57.6\\&#10;-----&-----&-----&-----\\&#10;\textit{mixture \$1.50/lb}&y&1.50&1.50y&#10;\end{array}

so... whatever "x" may be, we know that the whole mix will be "y" amount, thus x + 36 = y

and their total prices will also add up to 1.50y
thus  1.10x + 57.6 = 1.50y

thus     \bf \begin{cases}&#10;x+36=\boxed{y}\\&#10;1.10x+57.6=1.50y\\&#10;----------\\&#10;1.10x+57.6=1.50\left( \boxed{x+36} \right)&#10;\end{cases}

solve for "x", to see how much nuts will be added

what about "y"? well x + 36 = y
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Miguel started to run on a treadmill after setting Its timer for 61 minutes. The display says that he has finished 42% of his ru
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i think 26 minutes but i’m not sure
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