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Degger [83]
3 years ago
12

Which statement best compares the graphs of f(x)=[x] and f(x)=[x]? The two graphs are exactly the same. The open and closed circ

les are reversed. The open and closed circles are reversed, and the graph of f(x)=[x] shifts up. The open and closed circles are the same, but the graph of f(x)=[x] shifts up.

Mathematics
2 answers:
Artyom0805 [142]3 years ago
7 0
Unless, you have a typo the graphs are exactly the same. You have the same function listed and the equation is exactly the same. You have f(x) = [x] for both equations.
timurjin [86]3 years ago
6 0

Answer:

the open and closed circles are reversed and the graph of f(x)=ceil(x) i. e. least integer function shifts up.

Step-by-step explanation:

the explanation to this question could be clearly seen from the graph of these two functions.

as  for     0 ≤x<1 the floor function takes the value 0 everywhere and it has closed brackets at 0 and open brackets at 1, while for   0<x≤1 the ceiling function takes the value 1 and it has open brackets at 0 and closed brackets at 1 similarly the graph could be extended in the whole real line.


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\frac{5632 \mathrm{~cm}^{3}}{11 \mathrm{~cm}^{3}}=512\\\\$$\text{Therefore, Solid $A$ is 512 times larger thm Solid B}

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Tpy6a [65]

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