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Darina [25.2K]
3 years ago
11

What is the length of a rectangular rose garden with a width of 25 feet and a perimeter of 130 feet

Mathematics
1 answer:
anastassius [24]3 years ago
3 0
The answer is 40, since 25(2) is 50 and 130-50 is 80. 80/2 is 40
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Suppose you just received a shipment of twelve televisions. Three of them are defective. Assuming that two televisions are rando
lukranit [14]
<span>The probability that both televisons work is 18/33.
</span><span>The probability that at least one does not work is 15/33.
</span>
Let x = number of shipments, x = 12
P(defective) = 3/12
P(working) =  9/12
The probability that two randomly selected televisions are both working is:
9/12 * 8/11 = 72 / 132 or 18/33
P(2 working) = 18/33 
8/11 is used for the second selection since the number of televisions has been reduced due to the first selection.

The probability of 1 not working among the two can be solved through"
P(at least one defective among the 2) = 1 - <span>P(2 working) 
</span><span>P(at least one defective among the 2)  = 15/ 33
</span>

Thank you for posting your question. I hope you found you were after. Please feel free to ask me another.


4 0
4 years ago
Read 2 more answers
Evaluate 5x-x/y when x=4y and y=2
kirza4 [7]
................................

8 0
4 years ago
What’s the 5th term is 2,14,98
iragen [17]

\bold{\huge{\orange{\underline{ Solution }}}}

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

  • \sf{ 2 , 14 ,.... 98 }
  • <u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>

<h3><u>Solution </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>

<u>Therefore</u><u>, </u>

  • \sf{a1\: or \:1st\: term = 2 }
  • \sf{a2 \:or \:2nd\: term = 14 }
  • \sf{an \:or\: last\: term = 98}

<u>Here</u><u>, </u>

Common difference of an AP

\sf{ a2 - a1 }

\sf{ = 14 - 2}

\sf{ = 12}

Thus, The common difference is 12

<u>Now</u><u>, </u>

We know that,

\sf{an = a1 + ( n - 1 )d}

\sf{a5 = 2 + ( 5 - 1 )12}

\sf{a5 = 2 + 4 × 12}

\sf{a5 = 2 + 48}

\sf{\red{a5 = 50}}

Hence, The 5th term of given AP is 50

4 0
2 years ago
Life tests performed on a sample of 13 batteries of a new model indicated: (1) an average life of 75 months, and (2) a standard
frozen [14]

Answer:

(71.28, 78.72)

Step-by-step explanation:

We have the following information from the statement:

mean (m) = 75

sample standard deviation (sd) = 5

Sample size (n) = 13

Significance level (alpha) = 1 - 0.98 = 0.02

Degrees of freedom for t-d (df) = n - 1 = 13 - 1 = 12

The critical value would be:

t (alpha / 2) / df = T (0.01) / 12 = 2,681 (this for the table)

Margin of error equals:

E = t (alpha / 2) / df * sd / n ^ (1/2), replacing:

E = 2,681 * 5/13 ^ (1/2)

E = 3.72

Therefore, the interval of 98% confidence interval would be:

75 + 3.72 = 78.72

75 - 3.72 = 71.28

(71.28, 78.72)

5 0
3 years ago
I need help with this question
Maslowich
20 divided by 2 equal 10 and the rest are counting by twos please
8 0
4 years ago
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