<span>The probability that both televisons work is 18/33.
</span><span>The probability that at least one does not work is 15/33.
</span>
Let x = number of shipments, x = 12
P(defective) = 3/12
P(working) = 9/12
The probability that two randomly selected televisions are both working is:
9/12 * 8/11 = 72 / 132 or 18/33
P(2 working) = 18/33
8/11 is used for the second selection since the number of televisions has been reduced due to the first selection.
The probability of 1 not working among the two can be solved through"
P(at least one defective among the 2) = 1 - <span>P(2 working)
</span><span>P(at least one defective among the 2) = 15/ 33
</span>
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<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>
What is the 5th term of an AP 2 , 14 ....98 .
<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>
<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

- <u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>
<h3><u>Solution </u><u>:</u><u>-</u></h3>
<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>
<u>Therefore</u><u>, </u>
<u>Here</u><u>, </u>
Common difference of an AP



Thus, The common difference is 12
<u>Now</u><u>, </u>
We know that,





Hence, The 5th term of given AP is 50
Answer:
(71.28, 78.72)
Step-by-step explanation:
We have the following information from the statement:
mean (m) = 75
sample standard deviation (sd) = 5
Sample size (n) = 13
Significance level (alpha) = 1 - 0.98 = 0.02
Degrees of freedom for t-d (df) = n - 1 = 13 - 1 = 12
The critical value would be:
t (alpha / 2) / df = T (0.01) / 12 = 2,681 (this for the table)
Margin of error equals:
E = t (alpha / 2) / df * sd / n ^ (1/2), replacing:
E = 2,681 * 5/13 ^ (1/2)
E = 3.72
Therefore, the interval of 98% confidence interval would be:
75 + 3.72 = 78.72
75 - 3.72 = 71.28
(71.28, 78.72)
20 divided by 2 equal 10 and the rest are counting by twos please