Hi There!
Given:
- A placemat requires 30 feet of ribbon
- Mandy has 200 feet of ribbon
To Find:
How many placemats can Mandy make, if she has 200 ft of ribbon?
Solve:
200÷30≈7
Thus, she can make 7 placemats.
<h3>Hope it helps & enjoy your day!</h3>
If one foot in real is 1/2 inches, then 1 inch in a blueprint is 2 feet. So a rectangle 18 by 22 inches will represent 18 * 2 by 22 * 2 feet in real. So the size of the yard is 36 by 44 feet.
Answer: You would need 512 cubic centimetres
Step-by-step explanation: The first approach to this question would be to understand the properties of the shape given in the question.
If a cube has an edge with length 8 cm, then all edges measure 8 cm as well. That is one property of a cube. Hence, the length, width and height all measure 8 cm each.
The volume of a cube is given as follows;
V = L x W x H (and the answer is expressed as V³)
Since the length , width and height all measure 8 cm, the volume can simply be expressed as
V = L x L x L
V = L³
V = 8³
V = 512 cm³
Therefore to completely fill a cube with edge length of 8 cm you would need 512 cubic centimetres.
Answer:
x = 25
Step-by-step explanation:
Angle 1 and the angle opposite from Angle 1 (the angle that's 68°) are vertical angles.
What are vertical angles, you ask?
According to the Oxford dictionary, vertical angles are each of the pairs of opposite angles made by two intersecting lines.
For example, take the letter X. The letter X has two lines that intersect to form 4 angles. The top and bottom angles are a pair of vertical angles. So are the left and right angles.
Vertical angles are always congruent.
(This is VERY important to know! It will help you solve many types of geometry problems!)
m1 is 3x - 7. Because Angle 1 and the angle that's 68° are vertical angles, that means they are equal to each other.
Therefore: 3x - 7 = 68.
Now, you can solve for x to get x = 25.
Hope this helps!
Answer:
See below ~
Step-by-step explanation:
Finding t₁₂ :
⇒ t₁₂ = t₁ + 11d
⇒ t₁₂ = 6 + 11(2)
⇒ t₁₂ = 6 + 22
⇒ t₁₂ = 28
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Finding S₁₂ :
⇒ S₁₂ = 12/2 × 2t₁ + (12 - 1)d
⇒ S₁₂ = 6 × 2(6) + 11(2)
⇒ S₁₂ = 6 × 12 + 22
⇒ S₁₂ = 6 × 34
⇒ S₁₂ = 204
