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stiks02 [169]
3 years ago
10

A school system is reducing the amount of dumpster loads of trash removed each week. In week 5, there were 40 dumpster loads of

waste removed. In week 10, there were 30 dumpster loads removed. Assume that the reduction in the amount of waste each week is linear. Write an equation in function form to show the amount of trash removed each week.
A. f(x) = - 2x + 40
B. f(x) = 2x + 40
C. f(x) = - 2x + 50
D. f(x) = 2x + 50
Mathematics
1 answer:
salantis [7]3 years ago
7 0

Answer: c

Step-by-step explanation:

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Instructions: Given one form of a sequence, write the other form.
Rufina [12.5K]

Answer:

The explicit formula is 15 + (n-1) -4

Step-by-step explanation:

The formula for an explicit formula is an = First number of the sequence (15) + (n-1)(times the amount of integers separating two different sequential numbers) which is -4.

For instance, since 15 is the first number, it will be a1 or 15. Next will be + (n-1) which is the same for every explicit sequence and the multiplier will be the difference between each number, which is -4 in the recursive sequence. As a result, the answer is 15 + (n-1) -4.

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I need help with this question, please
Xelga [282]

Answer:

10

Step-by-step explanation:

bh/2

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Find the area of the region enclosed by the graphs of these equations. (CALCULUS HELP)
sergiy2304 [10]

Answer:

\displaystyle A = \frac{20\sqrt{15}}{3}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  1. Multiplication Property of Equality
  2. Division Property of Equality
  3. Addition Property of Equality
  4. Subtraction Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients
  • Graphing
  • Exponential Rule [Root Rewrite]:                                                                   \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Area - Integrals

U-Substitution

Integration Rule [Reverse Power Rule]:                                                               \displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Property [Multiplied Constant]:                                                         \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Integration Property [Addition/Subtraction]:                                                       \displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx

Integration Rule [Fundamental Theorem of Calculus 1]:                                     \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Area of a Region Formula:                                                                                     \displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

F: y = √(15 - x)

G: y = √(15 - 3x)

H: y = 0

<u>Step 2: Find Bounds of Integration</u>

<em>Solve each equation for the x-value for our bounds of integration.</em>

F

  1. Set <em>y</em> = 0:                                                                                                         0 = √(15 - x)
  2. [Equality Property] Square both sides:                                                          0 = 15 - x
  3. [Subtraction Property of Equality] Isolate <em>x</em> term:                                         -x = -15
  4. [Division Property of Equality] Isolate <em>x</em>:                                                        x = 15

G

  1. Set y = 0:                                                                                                         0 = √(15 - 3x)
  2. [Equality Property] Square both sides:                                                          0 = 15 - 3x
  3. [Subtraction Property of Equality] Isolate <em>x</em> term:                                         -3x = -15
  4. [Division Property of Equality] Isolate <em>x</em>:                                                        x = 5

This tells us that our bounds of integration for function F is from 0 to 15 and our bounds of integration for function G is 0 to 5.

We see that we need to subtract function G from function F to get our area of the region (See attachment graph for visual).

<u>Step 3: Find Area of Region</u>

<em>Integration Part 1</em>

  1. Rewrite Area of Region Formula [Integration Property - Subtraction]:     \displaystyle A = \int\limits^b_a {f(x)} \, dx - \int\limits^d_c {g(x)} \, dx
  2. [Integral] Substitute in variables and limits [Area of Region Formula]:     \displaystyle A = \int\limits^{15}_0 {\sqrt{15 - x}} \, dx - \int\limits^5_0 {\sqrt{15 - 3x}} \, dx
  3. [Area] [Integral] Rewrite [Exponential Rule - Root Rewrite]:                       \displaystyle A = \int\limits^{15}_0 {(15 - x)^{\frac{1}{2}}} \, dx - \int\limits^5_0 {(15 - 3x)^{\frac{1}{2}}} \, dx

<u>Step 4: Identify Variables</u>

<em>Set variables for u-substitution for both integrals.</em>

Integral 1:

u = 15 - x

du = -dx

Integral 2:

z = 15 - 3x

dz = -3dx

<u>Step 5: Find Area of Region</u>

<em>Integration Part 2</em>

  1. [Area] Rewrite [Integration Property - Multiplied Constant]:                       \displaystyle A = -\int\limits^{15}_0 {-(15 - x)^{\frac{1}{2}}} \, dx + \frac{1}{3}\int\limits^5_0 {-3(15 - 3x)^{\frac{1}{2}}} \, dx
  2. [Area] U-Substitution:                                                                                   \displaystyle A = -\int\limits^0_{15} {u^{\frac{1}{2}}} \, du + \frac{1}{3}\int\limits^0_{15} {z^{\frac{1}{2}}} \, dz
  3. [Area] Reverse Power Rule:                                                                         \displaystyle A = -(\frac{2u^{\frac{3}{2}}}{3}) \bigg|\limit^0_{15} + \frac{1}{3}(\frac{2z^{\frac{3}{2}}}{3}) \bigg|\limit^0_{15}
  4. [Area] Evaluate [Integration Rule - FTC 1]:                                                   \displaystyle A = -(-10\sqrt{15}) + \frac{1}{3}(-10\sqrt{15})
  5. [Area] Multiply:                                                                                               \displaystyle A = 10\sqrt{15} + \frac{-10\sqrt{15}}{3}
  6. [Area] Add:                                                                                                     \displaystyle A = \frac{20\sqrt{15}}{3}

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Area Under the Curve - Area of a Region (Integration)

Book: College Calculus 10e

3 0
3 years ago
Which statement is false:
Nat2105 [25]

9514 1404 393

Answer:

  C. Equivalent ratios are ratios that name a different, unequal ratio.

Step-by-step explanation:

Statement C simply makes no sense. It cannot be considered to be true.

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Statement D seems to be missing a word: ... the rate is called a unit <em>rate</em>.

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