How many minutes is 7:43 to 8:41

If YV = 28 in, find the length of vyw

max2010maxim [7]

Answer:

I’m sorry I don’t know

Step-by-step explanation:

3 0

3 years ago

What is the highest multiple of 2 and 3?

zubka84 [21]

2 and 3 are prime numbers, so it means that the greatest common factor is:

G.C.M(2;3)=2*3=6

6 0

4 years ago

Use the appropriate compound interest formula to compute the balance in the account after the stated period of time 24,000 is in

VLD [36.1K]

We know the compound interest formula is given by

$A=P(1+\frac{r}{n} )^{nt}$

Now, we have been given that 24,000 is invested for 2 years with an APR of 6% and daily compounding. Thus, we have

$P= 24,000\\
\\
t=2\\
\\
r=0.06\\
\\
n=365$

On substituting these values in the above formula for the compound interest, we get

$A=24000\left ( 1+\frac{0.06}{365} \right )^{365\cdot 2}\\
\\
\text{On solving this, we get}\\
\\
A=27059.7$

Therefore, the balance in the account after 2 years is 27059.7

7 0

3 years ago

2). Bill has twice as many candies as Fred. Tim has 3 fewer than 3 times as many candles as Fred.

sasho [114]

Step-by-step explanation:

<h2>Answer:-</h2>

$\tt{Let \ the \ candies \ taken \ by \ Fred \ be \ x.}$

Now, let's Solve!

So, according to Question,

Bill = 2x

Tim = 3x-3

Total Candies = 177.

$\bf{x+2x+3x-3=177}$

Totalling x,

$\bf{6x-3=177}$

$\bf{6x=177+3}$

$\bf{6x = 180}$

$\boxed{\sf{x = 30}}$

So, Fred has 30 candies.

Bill's Candies = 2×30 = 60 Candies

Tim's Candies = 3×30-3 = 90-3 = 87 Candies.

Hope it helps :)

7 0

3 years ago

An elementary school class ran 1 mile in an average of 11 minutes with a standard deviation of 3 minutes. Rachel, a student in t

Natali5045456 [20]

Answer:

a) Kenji's time had a lower z-score, which means that he is better compared to other runners on his level, and better to his peers compared to Nedda.

b) Rachel, because her time had the lowest z-score.

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

The lower the time, the better the runner is. So whoever's time has a lower z-score is a better runner. So initially, we find the z-score of each student's time.

An elementary school class ran 1 mile in an average of 11 minutes with a standard deviation of 3 minutes. Rachel, a student in the class, ran 1 mile in 8 minutes.

This means that for Rachel's time, we have that $X = 8, \mu = 11, \sigma = 3$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{8 - 11}{3}$

$Z = -1$

A junior high school class ran 1 mile in an average of 9 minutes, with a standard deviation of 2 minutes. Kenji, a student in the class, ran 1 mile in 8.5 minutes.

This means that for Kenji's time, we have that $X = 8.5, \mu = 9, \sigma = 2$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{8.5 - 9}{2}$

$Z = -0.25$

A high school class ran 1 mile in an average of 7 minutes with a standard deviation of 4 minutes. Nedda, a student in the class, ran 1 mile in 8 minutes.

This means that for Nedda's time, we have that $X = 8, \mu = 7, \sigma = 4$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{8 - 7}{4}$

$Z = 0.25$

(a) Why is Kenji considered a better runner than Nedda, even though Nedda ran faster than he?

Kenji's time had a lower z-score, which means that he is better compared to other runners on his level, and better to his peers compared to Nedda.

(b) Who is the fastest runner with respect to his or her class? Explain why

Rachel, because her time had the lowest z-score.

8 0

3 years ago