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Dafna11 [192]
3 years ago
8

Which of the following is NOT a monomial?

Mathematics
1 answer:
Sergio [31]3 years ago
6 0
<span>3m + n is not a monomial since it is a binomial</span>
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Help me solve please! The math club has 57 members who are in sixth or seventh grades. There are twice as many sixth graders as
saul85 [17]
We know there is 57 members are in the math club and there is twice as many sixth grades than the seventh. To find out how many sixth graders are in the club, we do:

x = seventh graders
2x = sixth graders

2x + x = 3x

57=3x
57 ÷ 3 = 3x ÷3
19 = x

So there is 19 seventh graders and 19×2= 38 sixth graders
7 0
3 years ago
I’m a bit confused here
alekssr [168]
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Are one-one
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Identify function
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2 years ago
Of 80 t-shirts, 10% are white, 30% are blue and the rest are red. How many are red?
juin [17]
There is 60% of red t-shirts 40% of them are white and blue so the reds are 60%
6 0
3 years ago
Read 2 more answers
Explain how to model the division of –24 by –4 on a number line.
Troyanec [42]
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7 0
3 years ago
A scientist had 3 1/2 liters of vinegar. He poured 2/3 of the vinegar into beaker. He then used 3/5 of the vinegar in the beaker
valentinak56 [21]

Answer:

A)2100 ml

Step-by-step explanation:

Given total vinegar is 3 1/2 liters and the used vinegar is  3/5 of the vinegar in the beaker:

#First calculate the amount of vinegar not poured in the beaker:

V_o=V_t-V_b\\\\=3\frac{1}{2}(1-\frac{2}{3})\\\\=1\frac{1}{6}

#Calculate amount of vinegar used in experiment:

V_b=\frac{2}{3}V_t=\frac{2}{3}(3\frac{1}{2})=2\frac{1}{3}\\\\V_u=\frac{3}{5}V_b=\frac{3}{5}\times 2\frac{1}{3}=1\frac{2}{5}

#The unused vinegar is therefore calculated by subtracting the used vinegar from the total at the start of the experiment:

V_r=V_t-V_u\\\\=3\frac{1}{2}-1\frac{2}5}\\\\=2\frac{1}{10}\times 1000\ ml\\\\=2100\ ml

Hence, the unused vinegar is 2100 ml

8 0
3 years ago
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