Answer:
1.7 × 10⁻⁴
Step-by-step explanation:
The question relates to a two sample z-test for the comparison between the means of the two samples
The null hypothesis is H₀: μ₁ ≤ μ₂
The alternative hypothesis is Hₐ: μ₁ > μ₂

Where;
= 13.5
= 12
σ₁ = 2.5
σ₂ = 1.5
We set our α level at 0.05
Therefore, our critical z = ± 1.96
For n₁ = n₂ = 23, we have;

We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96
Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983
Therefore;
The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.
First, we need to find the LCD (Least Common Denominator) so we can subtract them much easier.
An easy way to find the LCD is to just multiply the denominators together: So 2 • 5 = 10
We have to do the same to the numerators too though.
1/2 (5) = 5/10
2/5 (2) = 4/10
Now, the remade expression is:
5/10 - 4/10 which will equal 1/10.
Hope it helped! If it did, please mark as Brainliest! :)
C- charge
H- hours
D- diagnostic fee
C= #H(90)+ D
C= 4.6(90)+50
=414+50
=$464
C-$800
H-?
D-50
C= #H(90)+50
800=H(90)+50
H(90)=800-50
H(90)=750
H(90)/90=750/90
H=750/90
H= 8.33333333
-1 5/12 You have to subtract one and 2/3 by one fourth and then take the negative from the tea and add it to your answer
This depends on the equation.