Question

I need fast help with step by step %20%7D%20%5C%2C%20dx" id="TexFormula1" title="\int\limits^2_1 {\frac{3x-1}{x+1} } \, dx" alt="\int\limits^2_1 {\frac{3x-1}{x+1} } \, dx" align="absmiddle" class="latex-formula">

Answer 1

Answer:

1.38 to the nearest hundredth.

Step-by-step explanation:

Dividing:

x + 1 ) 3x - 1 ( 3            

          3x + 3

                -4

so (3x - 1) / (x + 1) =  3  - 4 / x+ 1

Integral  of (3  - 4 / x+1 )  = 3x - 4 ln(x + 1)

Between  limits of 1 and 2 we have:

(3(2) - 4 ln 3) - (3 - 4 ln2)

=  1.6056 - 0.2274

= 1.3782.