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kherson [118]
3 years ago
6

The difference between two numbers is less than 0.

Mathematics
1 answer:
Serhud [2]3 years ago
4 0
The 2 numbers cannot be positive but the 2 numbers can be both positive and negative like: 2+(-3)= -1. Both numbers can also be negative like:  (-3)-(-2)=-1.
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4 Tan A/1-Tan^4=Tan2A + Sin2A​
Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
3 years ago
Nicolas has three fewer than twice the number of songs downloaded as Sabrina does.
EleoNora [17]
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3 0
3 years ago
Use the formula, I = PRT, to find the time if | = $387.50, P = $1,550, and R = 12.5%
stiks02 [169]

Answer:

T = 2

Step-by-step explanation:

Take the given formulaer

I = PRT

And plug in the variables you know (I, P, R)

387.50 = 1,550(.125)T

(12.5% becomes .125 after you divide it by 100, because precents are really just fractions out of 100)

387.50 = 193.75T

T = 2

8 0
2 years ago
Tanya says .53 is greater than .7 because 53 is greater than 7 Can you explain her mistake?
sergey [27]
Take 0.53 and 0.7 by 100 to make them percents. 0.53 times 100 is 53% and 0.7 time 100 is 70%. so 0.7>0.53
4 0
3 years ago
Read 2 more answers
2+2, you guys were helpfulllll.<br> : )
katrin2010 [14]

Answer:

The correct answer is 2+2=4

thanks

8 0
3 years ago
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