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kherson [118]
3 years ago
6

The difference between two numbers is less than 0.

Mathematics
1 answer:
Serhud [2]3 years ago
4 0
The 2 numbers cannot be positive but the 2 numbers can be both positive and negative like: 2+(-3)= -1. Both numbers can also be negative like:  (-3)-(-2)=-1.
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Solve for y: 10.3 = 0.6y
Mademuasel [1]
Y is being multiplied by 0.6 so you have to divide by 0.6 on both sides to leave y alone.
y=10.3/0.6
7 0
3 years ago
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How to understand the word problem well in the math?​
tensa zangetsu [6.8K]
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3 0
3 years ago
If f(x) = 3x^2 - 4x + 5 and g(x) = 2x^2 + 2,<br> find f(x) – g(x).<br><br> Answer: x^2 - 4x + 3
Nadusha1986 [10]

Answer:

f(x) – g(x) = x^2 - 4x + 3

Step-by-step explanation:

f(x) = 3x^2 - 4x + 5 and g(x) = 2x^2 + 2,

f(x) – g(x) = 3x^2 - 4x + 5 - ( 2x^2 + 2)

Distribute the minus sign

f(x) – g(x) = 3x^2 - 4x + 5 - 2x^2 - 2

  Combine like terms

f(x) – g(x) = x^2 - 4x + 3

 

5 0
2 years ago
Which equasion represents a line that is parallel to the line y=-4x+5
Debora [2.8K]
In order to be parallel to your line, a line has to have the same slope as your line. So it has to have slope −4
−
4
.

Thus any line parallel to the line =−4+5
y
=
−
4
x
+
5
has an equation of the form =−4+
y
=
−
4
x
+
b
, where
b
is any number.
4 0
3 years ago
The engine torque y (in foot-pounds) of one model of car is given by y=−3.75x2+23.2x+38.8, where x is the speed (in thousands of
Stels [109]

Answer:

Step-by-step explanation:

If the engine torque y (in foot-pounds) of one model of car is given by y=−3.75x^2+23.2x+38.8

The engine speed is at maximum if dy/dx = 0

dy/dx = -2(3.75)x+23.2

dy/dx = -7.5x + 23.2

since dy/dx = 0

0 =  -7.5x + 23.2

7.5x = 23.2

x = 23.2/7.5

x = 3.093

Hence the maximum torque is 3.09 rev/min

8 0
3 years ago
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