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2 years ago

Please help me with this sum

Mathematics

1 answer:

Maslowich2 years ago

4 0

Answer:

6327

1827

2418

832

742

606

3248

2127

5436

203 X 4=812

Step-by-step explanation:

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First right answer for both gets brain

kirza4 [7]

B 8:00 am

8:00+1:25=9:25
9:25+25=9:50
9:50+30=10:20

B $240

60×2=120×2=240

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3 years ago

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natali 33 [55]

Answer:

Answer is D.

Step-by-step explanation:

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2 years ago

What is the sum?? need help

SOVA2 [1]

43+35=78 the answer is 78

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3 years ago

Express the function as the sum of a power series by first using partial fractions. f(x) = 8 x2 − 4x − 12 f(x) = ∞ n = 0 find th

alexandr1967 [171]

I'm guessing the function is

$f(x)=\dfrac8{x^2-4x-12}=\dfrac8{(x-6)(x+2)}$

which, split into partial fractions, is equivalent to

$\dfrac1{x-6}-\dfrac1{x+2}$

Recall that for $|x|$ we have

$\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n$

With some rearranging, we find

$\dfrac1{x-6}=-\dfrac16\dfrac1{1-\frac x6}=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n$

valid for $\left|\dfrac x6\right|$ , or $|x|$ , and

$\dfrac1{x+2}=\dfrac12\dfrac1{1-\left(-\frac x2\right)}=\displaystyle\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n$

valid for $\left|-\dfrac x2\right|$ , or $|x|$ .

So we have

$f(x)=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n-\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n$

$f(x)=\displaystyle-\sum_{n=0}^\infty\left(\frac{x^n}{6^{n+1}}+\frac{(-x)^n}{2^{n+1}}\right)$

$f(x)=\displaystyle-\sum_{n=0}^\infty\frac{1+3(-3)^n}{6^{n+1}}x^n$

Taken together, the power series for $f(x)$ can only converge for $|x|$ , or $-2$ .

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3 years ago

What is GCF mean and Lcm ?

stich3 [128]

GCF means greatest common factor and LCM means least common multiple. ;)

6 0

3 years ago

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Please help me with this sum​

Please help me with this sum