$x^2 + 8x + 12 = 0\\ \\a=1 , b= 8, c= 12 \\ \\ \Delta =b^2-4ac = 8^2 -4\cdot1\cdot12= 64-48= 16\\ \\\Delta > 0 \\ \\ Answer : \ C. \ \ two \ rational \ solutions$

5 0

2 years ago

Read 2 more answers

Simplify the trigonometric expression sin(4x)+2 sin(2x) using Double-Angle

drek231 [11]

Answer:

${ \bf{ = \sin(4x) + 2 \sin(2x) }} \\ = { \bf{2 \sin(2x) \cos(2x) + 4 \sin(x) \cos(x) }} \\ { \bf{ = 4 \sin(x) \cos(x) . ({ \cos }^{2} x - { \sin}^{2} }x) + 4 \sin(x) \cos(x) } \\ = { \bf{4 \sin(x) \cos(x) ( { \cos }^{2}x - { \sin }^{2}x + 1) }} \\ = { \bf{4 \sin(x) \cos(x) }(2 { \cos }^{2} x)} \\ = { \bf{8 \sin(x) { \cos}^{3}x }}$

8 0

2 years ago

*THIS IS FROM K12 MIDDLE SCHOOL*

AlexFokin [52]

Answer:

Step-by-step explanation:

the answer is 7 because -4 in the first pair and 3 from the second ordered pair is 7.The other side is 4 because 2 and -2 are 4 places away from each other

hope it helps :)

7 0

2 years ago

Read 2 more answers

Hiii please help i’ll give brainliest if you give a correct answer tysm!

taurus [48]

20 people

Reason - following the sequence

8 0

2 years ago

Which equation is correct?sin hº = Z÷xsin h°= x÷zcos h°=z÷xcos h°=x÷z​

Which equation is correct?sin hº = Z÷xsin h°= x÷zcos h°=z÷xcos h°=x÷z