Answer:
See below ↓
Step-by-step explanation:
<u>Solve for x.</u>
<u>2.1.1</u>
- px + qx = a
- x (p + q) = a
- <u>x = a / (p + q)</u>
<u></u>
<u>2.1.2</u>
- 2x² - 5x + 2 = 0
- 2x² - 4x - x + 2 = 0
- 2x(x - 2) - 1(x - 2) = 0
- (2x - 1)(x - 2) = 0
- <u>x = 1/2, 2</u>
<u></u>
<u>2.1.3</u>
- <u />
= 32 ![2x^{-3x-1} = 2^{5}](https://tex.z-dn.net/?f=2x%5E%7B-3x-1%7D%20%3D%202%5E%7B5%7D)
- -3x - 1 = 5
- -3x = 6
- <u>x = -2</u>
<u></u>
<u>I can only answer 3 questions together at maximum so kindly post the rest of your questions 3 at a time separately.</u>
<u></u>
<u>Hope this helped~</u>
Answer:
No, H is not a subspace of the vector space V.
Step-by-step explanation:
A matrix is a rectangular array in which elements are arranged in rows and columns.
A matrix in which number of columns is equal to number of rows is known as a square matrix.
Let H denote set of all 2×2 idempotent matrices.
H is a subspace of a vector space V if
for
and
.
Let ![A=\begin {pmatrix}1&0\\0&1 \end{pmatrix}](https://tex.z-dn.net/?f=A%3D%5Cbegin%20%7Bpmatrix%7D1%260%5C%5C0%261%20%5Cend%7Bpmatrix%7D)
As
, A is idempotent.
So, ![A \in H](https://tex.z-dn.net/?f=A%20%5Cin%20H)
So, A+A is not idempotent and hence, does not belong to H.
So, H is not a subspace of the vector space V.
Answer:
vwt and xwy
Step-by-step explanation:
let me know if you need an explanation!
Answer:
(-2,3)
Step-by-step explanation:
(-2,3) hope this helps
Answer:
slope is 2/3, the y-intercept is -4
Step-by-step explanation:
y=mx+b
m is always the slope. b is always the y-intercept. please give brainliest!!