C - (x-3)^2=36
If we expand (x-3)^2=36:
(x-3)(x-3)=36
x^2-3x-3x+9=36
x^2-6x+9=36
Then subtract 36
x^2-6x-27=0
Answer:
12 cm
Step-by-step explanation:
The square of the length of the tangent segment is equal to the product of near and far distances to the circle from the point of intersection of the secant and tangent:
(8 cm)^2 = (4 cm)(4 cm +x)
16 cm = 4 cm +x . . . . . . divide by 4 cm
12 cm = x . . . . . . . . . . . . subtract 4 cm
Answer:
Option A. ![f(x)=86[1.04]^{x}](https://tex.z-dn.net/?f=f%28x%29%3D86%5B1.04%5D%5E%7Bx%7D)
; grows approximately at a rate of 0.4% daily
Step-by-step explanation:
we have
where
f(x) the number of weeds in the garden
x ----> the number of weeks
Calculate how quickly the weeds grow each day
Remember that a week is equal to seven days
so
Using the law of exponents
b^(x/a) = b^(x*(1/a)) = (b^(1/a))^x
so
![f(x)=86[(1.29)^{\frac{1}{7}}]^{x}](https://tex.z-dn.net/?f=f%28x%29%3D86%5B%281.29%29%5E%7B%5Cfrac%7B1%7D%7B7%7D%7D%5D%5E%7Bx%7D)
therefore
The rate is approximately
1.04=1+r
r=1.04-1=0.04=4% daily
This is basically a simple problem to understand. The only thing that needs to be done is to divide the mass of the sun by the mass of mercury. It will give the required result.
Number of times the mass of sun is greater than
the mass of mercury = 21.3525×102921.3525×1029/<span>328.5×1021328.5×1021
= </span><span>7.1783629e+15
I hope that this is the answer that you were looking for and it has come to your great help.</span>
