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2 years ago

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Puzzle 3

1 answer:

tankabanditka [31]2 years ago

8 0

Answer:

DIBF

Step-by-step explanation:

It is helpful to look at the value of the y-intercept and the sign of the slope. The y-intercept is the y-value where the line crosses the y-axis. The slope is the "rise" divided by the "run". You can count horizontal and vertical grid squares between the y-intercept and the next grid crossing to determine the slope.

The slope-intercept equation is ...

y = mx + b . . . . . . . line with slope m and y-intercept b

__

<h3>1.</h3>

y-intercept is -3, slope is negative (-1/3). Matches choice D.

<h3>2.</h3>

y-intercept is 0. Matches choice I.

<h3>3. </h3>

y-intercept is 1, slope is negative and is steep (-3). Matches choice B.

<h3>4.</h3>

y-intercept is 3, slope is negative (-1/2). Matches choice F.

The code is DIBF.

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Determine the zeros of the function <br> 5) y=-x² + 2x + 1

Rus_ich [418]

<h3>Zeros of function are $x = 1 + \sqrt{2} \text{ and } x = 1 - \sqrt{2}$ </h3>

<em><u>Solution:</u></em>

<em><u>We have to find the zeros of the function</u></em>

$y = -x^2 + 2x+1$

Find the zeros of function:

$-x^2 + 2x+1 = 0\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=-1,\:b=2,\:c=1\\\\x =\frac{-2\pm \sqrt{2^2-4\left(-1\right)1}}{2\left(-1\right)}$

$Simplify\\\\x=\frac{-2 \pm \sqrt{4+4}}{-2}\\\\x =\frac{-2 \pm \sqrt{8}}{-2}\\\\Simplify\\\\x =\frac{-2 \pm 2 \sqrt{2}}{-2}\\\\x = 1 \pm \sqrt{2}$

We have two zeros

$x = 1 + \sqrt{2} \text{ and } x = 1 - \sqrt{2}$

Thus zeros of function are $x = 1 + \sqrt{2} \text{ and } x = 1 - \sqrt{2}$

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A closed circle means greater than or equal to and less than or equal to.
An open circle is greater than or less than.

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A theater sells adult tickets for $8.00 and children's tickets for $5.50. Sally bought some of each kind (not the same number) a

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An athlete ran 200 meters in 19.19 seconds. Suppose that he ran the first half of that race (around a curve) in 10.75 seconds. H

SOVA2 [1]

The time needed to run the second half of the race is 8.44 s

Step-by-step explanation:

The total distance covered by the athlete during the race is

d = 200 m

And the total time taken to cover this distance is

T = 19.19 s

We also know that the time the athlete needs to cover the first half of the race is

$t_1 = 10.75 s$

Also, we know that

$T=t_1 + t_2$

where $t_2$ is the time the athlete takes to cover the second half of the race.

Re-arranging this equation and susbtituting the values, we find the value of t2:

$t_2 = T-t_1 = 19.19-10.75=8.44 s$

Learn more about uniform motion:

brainly.com/question/8893949

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3 years ago

Help me please thank you :)

Radda [10]

I have no idea but good luck

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