All categories

3 years ago

When you ask the database more complex questions using comparison operators, you are conducting a _____?

2 answers:

7 0

When you ask the database more complex questions using comparison operators, you are conducting a query.
The term "query" denotes a programmatic statement that is understand by a the DBMS(Database management system) that understands how to access and manipulate data within a database.

Lostsunrise [7]3 years ago

6 0

When you ask the database more complex questions using comparison operators, you are conducting a Query.
A Query-is an inquiry into the database using the SELECT statement.It is used to extract data from the database in a readable format according to the users request.

You might be interested in

Computer A has an overall CPI of 1.3 and can be run at a clock rate of 600 MHz. Computer B has a CPI of 2.5 and can be run at a

kirill115 [55]

Answer:

Check the explanation

Explanation:

CPI means Clock cycle per Instruction

given Clock rate 600 MHz then clock time is Cー 1.67nSec clockrate 600M

Execution time is given by following Formula.

Execution Time(CPU time) = CPI*Instruction Count * clock time = $\frac{CPI*Instruction Count}{ClockRate}$

for system A CPU time is 1.3 * 100, 000 600 106

= 216.67 micro sec.

for system B CPU time is $=\frac{2.5*100,000}{750*10^6}$

= 333.33 micro sec

c) Since the system B is slower than system A, So the system A executes the given program in less time

Hence take CPU execution time of system B as CPU time of System A.

therefore

216.67 micro = = $\frac{2.5*Instruction}{750*10^6}$

Instructions = 216.67*750/2.5

= 65001

hence 65001 instruction are needed for executing program By system B. to complete the program as fast as system A

3 0

3 years ago

Bytes are typically represented with a lowercase b and bits with an uppercase B. true or false

34kurt

Answer:

False

Explanation:

Byte(B) is uppercase

bit(b) is lowercase

Good way to remember is that its takes 8 bits makes a byte. In other word, a byte is bigger than a bit so it makes sense that byte is uppercase.

7 0

3 years ago

Can you help me with Computer issues graphic organizer? Will give out brainly

tino4ka555 [31]

Just put for first: coding, graphics and for second : designing, writing
Third?: put all of the abov

6 0

3 years ago

What are the advantages of renting a home over buying a home? What are some disadvantages?

weqwewe [10]

An advantage of renting a home is that you don't have to fix any appliances or structures of the home your landlord does that for you. disadvantages are you have to follow their rules, you can't change anything on the inside like the paint or add a room to the home. in the state of Washington and landlord can evict you with only 20 days notice if they want to permanently sell the property. that's called a no-fault eviction. that's all I can think of hope that helps

7 0

3 years ago

In Java.Use a single for loop to output odd numbers, even numbers, and an arithmetic function of an odd and even number. Use the

rosijanka [135]

Answer:

This program is written using java programming language

Difficult lines are explained using comments (See Attachment for Source file)

Program starts here

import java.util.*;

import java.lang.Math;

public class oddeven{

public static void main(String [] args)

{

double even,odd;//Declare variables even and odd as double

//The next iteration prints odd numbers

for(int i = 1;i<=173;i+=2)

{

odd = i;

System.out.format("%.4f",odd);//Round to 4 decimal places and print

System.out.print("\t");

}

System.out.print('\n');//Start printing on a new line

//The next iteration prints even numbers

for(int i = 0;i<=173;i+=2)

{

even=i;

System.out.format("%.4f",even);//Round to 4 decimal places and print

System.out.print("\t");

}

System.out.print('\n');//Start printing on a new line

double ssqrt;//Declare ssqrt to calculate the square root of sum of even and odd numbers

for(int i = 0;i<=173;i+=2)

{

ssqrt = Math.sqrt(2*i+1);//Calculate square root here

System.out.format("%.4f",ssqrt); //Round to 4 decimal places and print

System.out.print("\t");

}

Explanation:

Libraries are imported into the program

import java.util.*;

import java.lang.Math;

The following line declares variables even and odd as double

double even,odd;

The following iteration is used to print odd numbers with in the range of 0 to 173

for(int i = 1;i<=173;i+=2) {

odd = i;

System.out.format("%.4f",odd); This particular line rounds up each odd numbers to 4 decimal places before printing them

System.out.print("\t"); This line prints a tab

}

The following code is used to start printing on a new line

System.out.print('\n');

The following iteration is used to print even numbers with in the range of 0 to 173

for(int i = 0;i<=173;i+=2)

{

even=i;

System.out.format("%.4f",even); This particular line rounds up each even numbers to 4 decimal places before printing them

System.out.print("\t"); This line prints a tab

}

The following code is used to start printing on a new line

System.out.print('\n');

The next statement declares ssqrt as double to calculate the square root of the sum of even and odd numbers

double ssqrt;

for(int i = 0;i<=173;i+=2)

{

ssqrt = Math.sqrt(2*i+1);This line calculates the square root of sum of even and odd numbers

System.out.format("%.4f",ssqrt); This particular line rounds up each even numbers to 4 decimal places before printing them