Answer:
#include<iostream>
using namespace std;
int lcm(int m, int n) {
int a;
a = (m > n) ? m: n;
while (true) {
if (a % m == 0 && a % n == 0)
return a;
++a;
}
}
int gcd(int m, int n) {
int r = 0, a, b;
a = (m > n) ? m : n;
b = (m < n) ? m : n;
r = b;
while (a % b != 0) {
r = a % b;
a = b;
b = r;
}
return r;
}
int main(int argc, char **argv) {
cout << "Enter the two numbers: ";
int m, n;
cin >> m >> n;
cout << "The LCM of two numbers is: " << lcm(m, n) << endl;
cout << "The GCD of two numbers is: " << gcd(m, n) << endl;
return 0;
}
Explanation:
Answer:
// program in Python to check perfect number
#function to find number is perfect or not
def is_Perfect_Number(n):
#total variable
tot = 1
i = 2
#sum of all divisor of number
while i*i<=n:
if n%i==0:
tot = tot + i + n/i
if tot == n and n != 1:
return 1
i = i+1
return 0
#read until user enter a perfect number
while True:
#read integer
num = int(input("Input an integer: "))
#call the function
if(is_Perfect_Number(num)):
print(num,"is perfect number")
#if perfect number break
break
else:
print(num,"is not a perfect number")
#ask again
print("try again.")
Explanation:
Read number from user and then call the function is_Perfect_Number() with parameter "num".This will find the sum of all divisor of number.If sum is equal to number then it will return 1 else return 0.If the number is not perfect then it will again ask to enter a number until user enter a perfect number.
Output:
Input an integer: 24
24 is not a perfect number
try again.
Input an integer: 28
28 is perfect number
Answer:
Yes this statement is true
Explanation:
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