Answer:
The circumference is 16π or 50.2654 depending on whether they ask you for an exact value or in terms of pi.
Step-by-step explanation:
2r=d
2(8)=d
16=d
C=πd
C=π16
So, the circumference is 16π or 50.2654 depending on whether they ask you for an exact value or in terms of pi.
The picture shows the answer I got!
Also! For the future, I use a site called
math way and it is great for problems like these.
Answer:
No solutions.
Step-by-step explanation:
9|x-1|=-45
Divide 9 into both sides.
|x-1| = -45/9
|x-1| = -5
Absolute value cannot be less than 0.
Answer:
a. ![30.36\ cm^2](https://tex.z-dn.net/?f=30.36%5C%20cm%5E2)
b. ![1.6\ cm](https://tex.z-dn.net/?f=1.6%5C%20cm)
Step-by-step explanation:
a. You know that the dimensions of Rectangle A are ![2\ cm* 3\frac{1}{5}\ cm=2\ cm* 3.2 cm](https://tex.z-dn.net/?f=2%5C%20cm%2A%203%5Cfrac%7B1%7D%7B5%7D%5C%20cm%3D2%5C%20cm%2A%203.2%20cm)
Since Rectangle B’s dimensions are
(which is 0.6 cm) larger than Rectangle A’s dimensions, then the dimensions of Rectangle B are:
![(2\ cm+0.6\ cm)( 3.2\ cm+0.6\ cm)=2.6\ cm*3.8\ cm](https://tex.z-dn.net/?f=%282%5C%20cm%2B0.6%5C%20cm%29%28%203.2%5C%20cm%2B0.6%5C%20cm%29%3D2.6%5C%20cm%2A3.8%5C%20cm)
Since Rectangle C’s dimensions are
(which is 0.6 cm) larger than Rectangle B's dimensions, then the dimensions of Rectangle C are:
![(2.6\ cm+0.6\ cm)( 3.8\ cm+0.6\ cm)=3.2\ cm*4.4\ cm](https://tex.z-dn.net/?f=%282.6%5C%20cm%2B0.6%5C%20cm%29%28%203.8%5C%20cm%2B0.6%5C%20cm%29%3D3.2%5C%20cm%2A4.4%5C%20cm)
The find the total area of all three rectangles you must add the products obtained when you multiply their dimensions. Then:
![A_t=(2\ cm* 3.2 cm)+(2.6\ cm*3.8\ cm)+(3.2\ cm*4.4\ cm)\\\\A_t=30.36\ cm^2](https://tex.z-dn.net/?f=A_t%3D%282%5C%20cm%2A%203.2%20cm%29%2B%282.6%5C%20cm%2A3.8%5C%20cm%29%2B%283.2%5C%20cm%2A4.4%5C%20cm%29%5C%5C%5C%5CA_t%3D30.36%5C%20cm%5E2)
b. The perimeter of a rectangle can be calculated with this formula:
![P=2l+2w](https://tex.z-dn.net/?f=P%3D2l%2B2w)
Where "l" is the lenght and "w" is the width.
Knowing the dimensions of each rectangleg, you can calculate the total perimeter as follows:
![P_t=(2)[(2\ cm+ 3.2 cm)+(2.6\ cm+3.8\ cm)+(3.2\ cm+4.4\ cm)]\\\\P_t=38.4\ cm](https://tex.z-dn.net/?f=P_t%3D%282%29%5B%282%5C%20cm%2B%203.2%20cm%29%2B%282.6%5C%20cm%2B3.8%5C%20cm%29%2B%283.2%5C%20cm%2B4.4%5C%20cm%29%5D%5C%5C%5C%5CP_t%3D38.4%5C%20cm)
Then, if a 40-cm coil of wire was used to form the rectangles, the amount of wire that is left is:
![40\ cm-38.4\ cm=1.6\ cm](https://tex.z-dn.net/?f=40%5C%20cm-38.4%5C%20cm%3D1.6%5C%20cm)
Answer:
it can be 4 or five depending on wich other way