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dimaraw [331]
2 years ago
14

Joel spends 272727 more minutes playing soccer after school on Tuesday than he did on Monday. He still exercises for a total of

606060 minutes after school.
What percent of his time exercising after school did Joel spend playing soccer on Tuesday?
Mathematics
1 answer:
Nookie1986 [14]2 years ago
6 0

Joel spent 72.5% of his time exercising after playing soccer on Tuesda

<h3>How to determine the percentage?</h3>

The given parameters are

Minutes spent on Tuesday = 27 more minutes than Monday

Total minutes spend = 60

This means that

Tuesday = Monday + 27

Monday + Tuesday = 60

Make Monday the subject in Tuesday = Monday + 27

Monday = Tuesday - 27

Substitute Monday = Tuesday - 27 in Monday + Tuesday = 60

Tuesday - 27 + Tuesday = 60

Evaluate

2 * Tuesday = 87

Divide by 2

Tuesday = 43.5

The percentage of time spent exercising on Tuesday is then calculated as

Percentage = 43.5/60 * 100%

Evaluate the expression

Percentage = 72.5%

Hence, Joel spent 72.5% of his time exercising after playing soccer on Tuesday

Read more about percentages at:

brainly.com/question/843074

#SPJ1

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Plz help me
Iteru [2.4K]

Answer:

I think the answer is 60 feet.

Step-by-step explanation:

Because his rate is 2 feet per second and the question asks where he'll be after 30 seconds, the answer has to be 60 feet.

I hope this helps!

5 0
3 years ago
Jessica and Maria got to the supermarket to buy fruit. Jessica
Burka [1]

Answer:$0.25 per apple

$0.30 per orange

Step-by-step explanation:

I knowwww iM aMbitious and i helped 126

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3 0
3 years ago
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)
vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

x^{\frac{2}{3}}+y^{\frac{2}{3}}=4

We have to find the equation of tangent line to the given curve at point (-3\sqrt3,1)

By using implicit differentiation, differentiate w.r.t x

\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0

Using formula :\frac{dx^n}{dx}=nx^{n-1}

\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}

\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}

\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}

Substitute the value x=-3\sqrt3,y=1

Then, we get

\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}

\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}

Slope of tangent=m=\frac{1}{\sqrt3}

Equation of tangent line with slope m and passing through the point (x_1,y_1) is given by

y-y_1=m(x-x_1)

Substitute the values then we get

The equation of tangent line is given by

y-1=\frac{1}{\sqrt3}(x+3\sqrt3)

y-1=\frac{x}{\sqrt3}+3

y=\frac{x}{\sqrt3}+3+1

y=\frac{x}{\sqrt3}+4

This is required equation of tangent line to the given curve at given point.

8 0
3 years ago
Given f(x)=x-10 . what is f(-7)?
Tomtit [17]
F(-7) = -7 - 10

f(-7) = -17


Hope I helped!

Let me know if you need anything else!

<span>~ Zoe (Rank:'Genius')</span>
8 0
3 years ago
Help with this question quick???
SIZIF [17.4K]
Mars is the correct answer
8 0
3 years ago
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